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Veronika [31]
3 years ago
5

Calculate the maximum mass of a metal, with equivalent mass of 20 g, that should be used in an equivalent mass determination wit

h a 100-mL eudometer tube for collection. For the purposes of calculation, assume 80 mL of hydrogen gas produced at standard conditions. (Round to 2 sig figs)
Chemistry
1 answer:
elena55 [62]3 years ago
7 0

Answer:

Explanation:

In the equivalent mass measurement , one gram equivalent of metal produces 11200 mL of hydrogen gas .

11200 mL hydrogen gas is produced by 1 gram equivalent of gas at STP

11200 mL hydrogen gas is produced by 20 g  of gas at STP

80 mL hydrogen gas is produced by 20 x 80 / 11200  g  of gas at STP

= 142.85 mg .

= 140 mg . ( rounded to 2 sig figures )

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Which statement best describes covalent bonding?
almond37 [142]

Answer:

Option C. Electrons are shared between two atoms

Explanation:

Covalent bonding is a type of bonding which exist between two non metals.

In this bonding, electrons are shared between the two atoms involved in order to attain a stable octet configuration.

This can be seen when hydrogen atom combine with chlorine atom to form hydrogen chloride as shown below:

H + Cl —> HCl

Hydrogen has 1 electron in it's outmost shell and it requires 1 electron to attain a stable configuration.

Chlorine has 7 electrons in it's outmost shell and requires 1 electron to attain a stable configuration.

During bonding, both hydrogen and chlorine will contribute 1 electron each to form bond, thereby attaining a stable configuration. The bond formed in this case is called covalent bond as both atoms involved shared electron to attain a stable configuration.

3 0
4 years ago
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8 0
3 years ago
Read 2 more answers
You have 2.394 x 102 mL of oxygen gas (O2) at 7.20 x 102 mm of Hg and 78 oC.
igomit [66]
We are given with
V = <span>2.394 x 102 mL 
P = </span><span>7.20 x 102 mm of Hg
T = </span><span>78 oC

We are asked to determine the mass of the sample in milligrams
Using the ideal gas law
n = PV / RT
n = </span>7.20 x 102 mm of Hg (2.394 x 102 mL) / R (78 + 273)
Use the appropriate value for R or just convert the values to SI and use R = 8.314
Then, solve for the mass of the sample by using the MW Oxygen which is 16 g/mol
3 0
3 years ago
How many oxygen atoms are contained in the following chemical formula? 2agno3
sesenic [268]

It would be: 2*3 = 6 oxygen atoms

OPTION D IS YOUR ANSWER......

7 0
4 years ago
How many gallons of a 60​% antifreeze solution must be mixed with 70 gallons of 25​% antifreeze to get a mixture that is 50​% ​a
Neporo4naja [7]

Answer:

The answer to your question is 175 gallons

Explanation:

Data

60% antifreeze solution  volume = ? = x

25% antifreeze solution   volume = 25%

Final concentration 50%

Process

              0.6x + 0.25(70) = 0.5(70 + x)

Simplification

              0.6x + 17.5 = 35 + 0.5x

              0.6x - 0.5x = 35 - 17.5

                          0.1x = 17.5

                              x = 17.5/0.1

Result

                              x = 175 gallons

6 0
4 years ago
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