Osmolarity=osmole of the solute/litres of the solution
ionic equation for dissociation of CaCl2 is
CaCl2--->Ca2+ +2Cl-
total osmoles for reaction are 1(Ca2+) + 2(Cl-)= 3 osmoles
therefore
0.50 moles of CaCl2 x 3 osmoles/ 1mole of CaCl2 = 1.5osmoles
osmolarity=1.5 /1.0 L=1.5 osmol/l
Supplementary angles add up to 180, so
6x+60+90 = 180 and solve for x
6x= 30
x=5
D acid and bases are the same
Answer:
total weight to expect = 331.60 grams
Explanation:
The flask wanted to be charged with 1.6 grams of sugar. The empty flask was weighed on a balance and it was determined to weigh 330 grams . The weight we would expect when we add the sugar can be computed as follows:
weight of the empty flask = 330 grams
weight of the sugar = 1.6 grams
The weight of the flask after adding the sugar will be the sum of the weight of the sugar and the empty falsk
Therefore,
Total weight to expect = 330 grams + 1.6 grams
total weight to expect = 331.60 grams
Here is the answer for your question which the mole of chlorine is 1.34
