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Marina CMI [18]
3 years ago
8

Sale! 60% OFF

Mathematics
1 answer:
ra1l [238]3 years ago
8 0
$12 hope this helps hehehehehe
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Please help with this Piecewise problem!!
tino4ka555 [31]

Remark

That was well worth doing. Desmos gave you the answer to the graph. Unfortunately I can only give you the correct graph. You will have to figure out from the choices which one is the correct answer -- or edit it so I can see what the rest of the question is.

Graph

The red one is f(x) is x + 3 {x <= -2}

The blue one is f(x) is x^2 - 1 {-2 <x <1} Notice the gap at 2. It is not continuous

The green one is f(x) is log_2(-x + 3)  {1 <=x < 3} and there is a gap between the blue and green one.

4 0
3 years ago
I will mark you
Nana76 [90]

Answer:

Yes, because the x's do not have more than one y.

Step-by-step explanation:

x      y

0      0

5       10

6       12

10     20

(That's meant to be a table). Looking at the x and y table values, you can see that none of the x's have two y's. So, this relation is a function.

7 0
3 years ago
When it rains I get tired. It's raining today. I'm going to take a nap.
tankabanditka [31]

Answer:

None of the Above

Step-by-step explanation:

Hope this helps

7 0
3 years ago
The standard deviation of a point estimator is the _____. a. standard error b. sample statistic c. point estimate d. sampling er
ivann1987 [24]

The standard deviation of a point estimator is the <u>standard error.</u>

"The point estimate is used to estimate the exact value of any parameter. For example, an internet poll says that 45% of Americans are concerned for the environment."

"Point estimates is a good measure but the problem with this parameter is that the sample of the statistics may vary so that there is a chance of sampling error."

"As the researcher is unable to presume that closeness of the sample statistics parameter with respect to the parameter so researcher refers to calculate the standard error instead of point estimate."

To learn more about standard error here

brainly.com/question/13179711

#SPJ4

4 0
1 year ago
Rewrite in simplest radical form 1 over x^(−3/6). Show each step of your process.
meriva

\bf ~\hspace{7em}\textit{negative exponents} \\\\ a^{-n} \implies \cfrac{1}{a^n} ~\hspace{4.5em} a^n\implies \cfrac{1}{a^{-n}} ~\hspace{4.5em} \cfrac{a^n}{a^m}\implies a^na^{-m}\implies a^{n-m} \\\\\\ ~\hspace{7em}\textit{rational exponents} \\\\ a^{\frac{ n}{ m}} \implies \sqrt[ m]{a^ n} ~\hspace{10em} a^{-\frac{ n}{ m}} \implies \cfrac{1}{a^{\frac{ n}{ m}}} \implies \cfrac{1}{\sqrt[ m]{a^ n}}

\bf \rule{34em}{0.25pt}\\\\ \cfrac{1}{x^{-\frac{3}{6}}}\implies x^{\frac{3}{6}}\implies x^{\frac{1}{2}}\implies \sqrt[2]{x^1}\implies \sqrt{x}

5 0
3 years ago
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