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devlian [24]
3 years ago
5

Rewrite in simplest radical form 1 over x^(−3/6). Show each step of your process.

Mathematics
1 answer:
meriva3 years ago
5 0

\bf ~\hspace{7em}\textit{negative exponents} \\\\ a^{-n} \implies \cfrac{1}{a^n} ~\hspace{4.5em} a^n\implies \cfrac{1}{a^{-n}} ~\hspace{4.5em} \cfrac{a^n}{a^m}\implies a^na^{-m}\implies a^{n-m} \\\\\\ ~\hspace{7em}\textit{rational exponents} \\\\ a^{\frac{ n}{ m}} \implies \sqrt[ m]{a^ n} ~\hspace{10em} a^{-\frac{ n}{ m}} \implies \cfrac{1}{a^{\frac{ n}{ m}}} \implies \cfrac{1}{\sqrt[ m]{a^ n}}

\bf \rule{34em}{0.25pt}\\\\ \cfrac{1}{x^{-\frac{3}{6}}}\implies x^{\frac{3}{6}}\implies x^{\frac{1}{2}}\implies \sqrt[2]{x^1}\implies \sqrt{x}

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I need help it’s due soon and i need help please also i solved one but i need three solved thanksssss
mel-nik [20]

Answer:

6) b = -13.55

8) p = -1

9) x = 7

4 0
3 years ago
5x - 4y = 19 <br> x + 2y = 8
klemol [59]

Answer:

(5x-4y)=19

5×19-4×19

95-76

19

Step-by-step explanation:

x+2y=8

x=8-2

x=6

7 0
3 years ago
Draw a line having a slope of 1/3 and y-intercept of -1
Lilit [14]
Equation for slope=1/3 and y-intercept=-1 is:
y = mx + b
where m is slope and b is y-intercept.
So, equation becomes
y = -1x + 1/3
Now put different values of x in the equation to get corresponding value of y.
x          y
0         1/3
1        -2/3
2        -5/3
3        -8/3
-1       4/3
-2       7/3
-3       10/3


8 0
3 years ago
The problem is in the picture :)
frozen [14]

Answer:

Last option: 4

Step-by-step explanation:

The quadratic equation simplified: x^2-4x=-\frac{7}{2} has the form:

ax^2+bx=c

In this case, you can identify that "a", "b" and "c" are:

a=1\\b=-4\\c=-\frac{7}{2}

To solve this quadratic equation  by completing the square, Carlos should add (\frac{b}{2})^2 to both sides of the equation. This is:

(\frac{-4}{2})^2=(-2)^2=4

Then:

x^2-4x+4=-\frac{7}{2}+4

Therefore you can observe that the number he should add to both sides of the equation is: 4

8 0
3 years ago
How many numbers lie between the square of 56 and 57
NARA [144]

Answer:

Given, two numbers 56 and 57 we need to find out the numbers lie between the squares of the given numbers.

Now, we have numbers lying between the square of n and (n + 1) is 2n

⇒ Numbers between squares of 56 and (56 + 1) = 2 × 56 = 112

Hence, 112 numbers lies between the square of the given numbers.

7 0
3 years ago
Read 2 more answers
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