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kirill115 [55]
3 years ago
11

THIRD TIME ASKING FOR HELP PLEASE HELP ME!!!!!!!!!!!!!!!!!!!

Mathematics
1 answer:
Fed [463]3 years ago
8 0
<h3>Answer:  9 units</h3>

========================================================

Explanation:

For now, focus on triangle ABD. This is a right triangle due to BD being an altitude.

Use the pythagorean theorem to find that...

(AD)^2 + (BD)^2 = (AB)^2

(1)^2 + (BD)^2 = (3)^2

1 + (BD)^2 = 9

(BD)^2 = 9-1

(BD)^2 = 8

Normally we would isolate BD itself, but I'll stop short and use that last line instead.

------------------

The triangles ABD and BCD are similar triangles (we can prove this using the AA similarity theorem).

Since we have similar triangles, we can form the proportion shown below

AD/BD = BD/CD

This cross multiplies to

AD*CD = (BD)^2

We know that AD = 1 and (BD)^2 = 8, so,

AD*CD = (BD)^2

1*CD = 8

CD = 8

This then means,

x = CD+DA

x = 8+1

x = 9

AC is 9 units long.

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4 years ago
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Answer:  

If the two side planks are equal lengths then the answer is 26 1/3.

3 0
2 years ago
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Sonja [21]

ΔABC is a 45 - 45 - 90 triangle. The pattern of its sides is as follows:

Each leg = 1 unit (and both legs are that way, since the triangle is isosceles - so two sides are the same)

Hypotenuse = √2 units.

So if we know either leg, we multiply by √2 to get the hypotenuse. In reverse, we divide by √2 if we know the hypotenuse to get the measurement of a leg.

Our problem tells us that the hypotenuse AC is 10 units. We divide 10 by √2 to get the measurement of leg AB. Since it's a 45 -45 - 90 triangle, AB = BC.

AB = \frac{10}{\sqrt{2}}

= \frac{10\sqrt{2}}{\sqrt{2}\sqrt{2}} to rationalize the radical

= \frac{10\sqrt{2}}{2} = 5\sqrt{2}

Thus, each leg is 5\sqrt{2} [/tex].

6 0
3 years ago
What is the greatest common factor of 12a and 9a2?<br><br> 9 <br> 36<br> 3a<br> 12a2
Virty [35]

Answer:

3a

Step-by-step explanation:

the common factors are what make up the terms. 12a is divisible by 3a

9a^2 is divisible by 3a

12a/3a = 4

9a^2/3a

(9a × 9a) / 3a = (9a × 3)

7 0
3 years ago
Read 2 more answers
Find the length of BE BC=3x+47 DE=10 BD=x+27 CE=x+26
adoni [48]

Answer:

B____C____D_____E

BC+ CE = BD + DE

(3x+47) + (x+26) = ( x+27) + (10)

4x + 73 = x + 37

4x – x = 37 – 73

3x = ‐ 36

x = – 36/ 3 —> x = – 12

BC = 3x + 47 = 3(-12) + 47 = - 36 + 47 = 11

BD = x+ 27 = –12+27 = 15

CE = x + 26 = –12+26= 14

<h3>So; </h3>

<h3>BE = BD+ DE = 15+ 10= 25</h3>

<h3><u>Or ;</u></h3>

<h3>BE= BC + CE = 11+ 14 = 25</h3>

I hope I helped you^_^

7 0
3 years ago
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