Our function f(x) can be rewritten if we factor out a common x^2 from each term:

Now inside the parentheses we have a polynomial of the form a^2 - b^2, or the difference of two perfect squares, which can be factored as (a+b)(a-b) so we have:

Setting our function equal to zero gives us the roots x = 0, x = 4, and x = -4.
The multiplicity of the root zero is two since it occurs twice, and the others are one since they occur only once. If you graph the function you can see that it will only touch the x-axis at x = 0, but will cross the x-axis at x = 4 and x = -4.
Answer:
If the two side planks are equal lengths then the answer is 26 1/3.
ΔABC is a 45 - 45 - 90 triangle. The pattern of its sides is as follows:
Each leg = 1 unit (and both legs are that way, since the triangle is isosceles - so two sides are the same)
Hypotenuse = √2 units.
So if we know either leg, we multiply by √2 to get the hypotenuse. In reverse, we divide by √2 if we know the hypotenuse to get the measurement of a leg.
Our problem tells us that the hypotenuse AC is 10 units. We divide 10 by √2 to get the measurement of leg AB. Since it's a 45 -45 - 90 triangle, AB = BC.

to rationalize the radical

Thus, each leg is 5\sqrt{2} [/tex].
Answer:
3a
Step-by-step explanation:
the common factors are what make up the terms. 12a is divisible by 3a
9a^2 is divisible by 3a
12a/3a = 4
9a^2/3a
(9a × 9a) / 3a = (9a × 3)
Answer:
B____C____D_____E
BC+ CE = BD + DE
(3x+47) + (x+26) = ( x+27) + (10)
4x + 73 = x + 37
4x – x = 37 – 73
3x = ‐ 36
x = – 36/ 3 —> x = – 12
BC = 3x + 47 = 3(-12) + 47 = - 36 + 47 = 11
BD = x+ 27 = –12+27 = 15
CE = x + 26 = –12+26= 14
<h3>So; </h3>
<h3>BE = BD+ DE = 15+ 10= 25</h3>
<h3><u>Or ;</u></h3>
<h3>BE= BC + CE = 11+ 14 = 25</h3>
I hope I helped you^_^