2 years ago

How do i do like how does it go cause i tryed doing it and i got the wrong answer each time

Mathematics

1 answer:

DIA [1.3K]2 years ago

8 0

Your grammar is wrong. You aren't asking a question. I don't want to be mean but yeah you need to ask a real question.

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Graph f(x) = 2x^4+3 let x = 0, 1, and 2. please show your work

mestny [16]

Sub those points for x
f(x) is the y

(x,y)

so for x=0
f(0)=2(0)^4+3
f(0)=0+3
f(0)=3
(0,3) is a opint

for x=1
f(1)=2(1)^4+3
f(1)=2(1)+3
f(1)=2+3
f(1)=5
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for x=2
f(2)=2(2^4)+3
f(2)=2(16)+3
f(2)=32+3
f(2)=35
(2,35) is another point

points are
(0,3)
(1,5)
(2,35)

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Step-by-step explanation:

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salantis [7]

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Answer:

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