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katen-ka-za [31]
3 years ago
10

Please help,Thanks;)

Mathematics
2 answers:
kap26 [50]3 years ago
4 0
840 as in one week he sees 70 patient and thus in 12 week 840...
alexdok [17]3 years ago
4 0
\tfrac{210}{3} = \tfrac{x}{12}
\newline

210*12 = 3x
\newline

2520 = 3x
\newline

\tfrac{2520}{3} = x
\newline

840 = x
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A circular pond 24 yd in
Schach [20]

Answer:

The walk will cost $8164.

Step-by-step explanation:

Given:

Diameter of the circular pond (D) = 24 yd

Width of the gravel path (x) = 2 yd

Cost per yard of the path = $50

Now, radius of the circular pond is half of the diameter and is given as:

Radius,R=\frac{D}{2}=\frac{24}{2}=12\ yd

Now, area of the pond is given as:

A_{pond}=\pi R^2=3.14\times (12)^2=3.14\times 144=452.16\ yd^2

Area of the complete path including the pond area is given as:

A_{outer}=\pi(R+x)^2=3.14\times(12+2)^2=3.14\times196=615.44\ yd^2

Now, area of the gravel path can be obtained by subtracting the pond area from the total outer area. This gives,

A_{path}=A_{outer}-A_{pond}\\\\A_{path}=615.44-452.16=163.28\ yd^2

Now, using unitary method,

Cost of 1 square yard of path = $50

∴ Cost of 163.28 square yard of path = 50 × 163.28 = $8164

Hence, the walk will cost $8164.

5 0
3 years ago
Read 2 more answers
In a group of 60 students, 18 students take Algebra I, 20 students take
melamori03 [73]

Answer:

32...................

7 0
2 years ago
8th grade math help!!
horsena [70]

Step-by-step explanation:

A = 1/2h(b1 + b2)

2A = h(b1 + b2)

h(b1 + b2) = 2A

h = 2A/(b1 + b2)

5 0
2 years ago
Please help me!!<br> 2(5– x)3 – 11=151
konstantin123 [22]

Answer:

x = -22

Step-by-step explanation:

2(5– x)3 – 11 = 151

(10 - 2x)3 - 11 = 151

30 - 6x = 162

-6x = 132

x = -22

5 0
3 years ago
Ms. Anguiano is enjoying a bicycle ride on a country road
GalinKa [24]

Answer:

The rate is 13 miles per hour

Step-by-step explanation:

* Lets explain how to solve the problem

- Jim lives three miles east of State College

- At noon, he leaves his house and begins to walk due east at a

constant speed of 2 miles per hour

- Annie lives four miles north of State College

- At noon, she leaves her house and begins to bicycle due north at a

constant speed of 8 miles per hour

- The east is perpendicular to the north

* Lets solve the problem

∵ At noon means 12 p.m

∵ They moved till 1 p.m

∵ Jim walked for 1 hour and Annie bicycled for 1 hour

∵ The rate of Jim is 2 miles per hour

∵ The rate of Annie is 8 miles per hour

- The distance = rate × time

∴ Jim walked = 2 × 1 = 2 miles

∴ Annie bicycled = 8 × 1 = 8 miles

- Lets calculate the distance of Jim from the State College till his

position at 1 p.m

∵ Jim lives three miles east of State College

∴ His distance at 1 p.m = 3 + 2 = 5 miles east

- Lats calculate the distance of Annie from the State College till her

position at 1 p.m

∵ Annie lives four miles north of State College

∴ Her distance at 1 p.m = 4 + 8 = 12 miles North

- Lets find the distance between them at 1 p.m

∵ The north ⊥ east

- Use Pythagoras Theorem to find the distance

∴ The distance = √(5² + 12)² = √(25 + 144) = √169 = 13 miles

- The rate = distance/time

∵ The distance between them is 13 miles in 1 hour

∴ The rate = 13/1 = 13 miles per hour

* The rate is 13 miles per hour

6 0
3 years ago
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