1) A. Biased because the population could be uneven. Too many of one ethnicity, too many of one gender, etc.
2) I believe this one is C. because there are not enough people. You need to survey the majority of parents instead of a selected few.
3) There are 80 green marbles per 500, therefore calculate the percentage.

or

percent. Multiply

percent or

times 25. It gives you

.
4) This one is a probability thing too. For every 500 batteries, there are 3 that are defective, therefore,

.

5) Yet another one. Add up all the nuts and you get

. The chance of getting a cashew from these

is:

.
Therefore:
keeping in mind that perpendicular lines have negative reciprocal slopes, let's check for the slope of the equation above

well then therefore

so we're really looking for the equation of a line with slope of -1/3 and that passes through (1, -3 )

Answer:
Step-by-step explanation:
The third, fifth and sixth expressions (from the top) are NOT polynomials, and the reason in each case is that the expression has one or more negative powers of x in it.
Answer:
v = 9
Step-by-step explanation:
50 = 6v - 4
50 + 4 = 6v
54 = 6v
6v/6 = 54/6
v = 9