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KengaRu [80]
3 years ago
10

What’s the constant?

Mathematics
2 answers:
anyanavicka [17]3 years ago
6 0
8 would be the constant but in this situation there is a variable next to it so I’m not sure if it would be considered a constant
Levart [38]3 years ago
4 0
Constants are numbers by themselves
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What are the zeros of f(x) = x2 - 12x + 36?
topjm [15]

Answer:

c. x = 6 only

Step-by-step explanation:

In order to calculate the zeros of f(x), we need to set it equal to zero and find the corresponding values of x.

x^{2}-12x+36=0

Using the midterm breaking, we can split -12x into two such terms whose sum will be -12x and product will be 36x². These two terms are -6x and -6x

So, the above expression can be written as:

x^2-6x-6x+36=0\\\\ x(x-6)-6(x-6)=0\\\\ (x-6)(x-6)=0\\\\ (x-6)^{2}=0\\\\ x-6=0\\\\ x=6

This means, the zero of f(x) occurs at x = 6 only.

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Graph A is the correct one
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Solve the y for the equation 5x-2y=10
eduard

Answer:

y = 5/2x - 5

Step-by-step explanation:

Step 1: Write equation

5x - 2y = 10

Step 2: Solve for <em>x</em>

  1. Subtract 5x on both sides: -2y = 10 - 5x
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