F(x) = 2^x; h(x) = x^3 + x + 8
Table
x f(x) = 2^x h(x) = x^3 + x + 8
0 2^0 = 1 0 + 0 + 8 = 8
1 2^1 = 2 1^3 + 1 + 8 = 10
2 2^2 = 4 2^3 + 2 + 8 = 8 + 2 + 8 = 18
3 2^3 = 8 3^3 + 3 + 8 = 27 + 3 + 8 = 38
4 2^2 = 16 4^3 + 4 + 8 = 76
10 2^10 = 1024 10^3 +10 + 8 = 1018
9 2^9 = 512 9^3 + 9 + 8 = 729 + 9 + 8 = 746
Answer: an approximate value of 10
Answer:4320cm
Step-by-step explanation:
(length of the arc)/(length of the radius)=central angle
lengthof the arc/20=216
lengthof the arc=216×20
length of the arc=4320cm
their is no question how can we answer this
4y+25=3y+20
4y+5=3y
***y=5***
so you plug y into both
4(5)+25 and 3(5)+20
45, 100, and 35 are the measurements of the angles.
<span>18c - 27d = 9(2c - 3d)
answer
</span><span>D) 9(2c - 3d)
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hope it helps
