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ahrayia [7]
3 years ago
13

Please help ASAP ! Please help ASAP !

Mathematics
2 answers:
mihalych1998 [28]3 years ago
5 0

Answer:

5/7

Step-by-step explanation:

4/7+1/7 is 5/7 and 5/7 is its simplest form. Hope this helps :)

Delicious77 [7]3 years ago
3 0

Answer:

the answer is 5/7

Step-by-step explanation:

hope it helps:)

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Four small cakes are shared equally among 5 children what part does each child receive?
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Answer:

0.8 of a cake

Step-by-step explanation:

all you do is divide 4 by 5

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What is 1000 to the power of 4
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1*10^12
Which means like 11 0's at the end of the 10
8 0
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What number when multiply by 24 gives u 24 an when subtract gives u 2
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4 0
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Suppose P varies directly with q and that P=36 when q=9 . <br> What is the value of P when q=3?
Yuri [45]

Answer:

P=12

Step-by-step explanation:

Since P=36 and q=9, this looks like a ratio of 4:1. So if q=3, multiply that value by 4 to get your answer

7 0
3 years ago
6-10 divide, another onee thank you!!​
eduard

Answers:

10.) \displaystyle \pm{5}

9.) \displaystyle 1\frac{1}{2}

8.) \displaystyle \pm{1\frac{1}{2}}

7.) \displaystyle \pm{1\frac{1}{2}}

6.) \displaystyle \pm{\frac{1}{2}}

Step-by-step explanations:

10.) \displaystyle \frac{\sqrt{200}}{\sqrt{8}} \hookrightarrow \sqrt{25} \hookrightarrow \frac{\pm{10\sqrt{2}}}{\pm{2\sqrt{2}}} \\ \\ \boxed{\pm{5}}

9.) \displaystyle \frac{\sqrt[3]{135}}{\sqrt[3]{40}} \hookrightarrow \sqrt[3]{3\frac{3}{8}} \hookrightarrow \frac{3\sqrt[3]{5}}{2\sqrt[3]{5}} \\ \\ \boxed{1\frac{1}{2}}

8.) \displaystyle \frac{\sqrt[4]{162}}{\sqrt[4]{32}} \hookrightarrow \sqrt[4]{5\frac{1}{16}} \hookrightarrow \frac{\pm{3\sqrt[4]{2}}}{\pm{2\sqrt[4]{2}}} \\ \\ \boxed{\pm{1\frac{1}{2}}}

7.) \displaystyle \frac{\sqrt{63}}{\sqrt{28}} \hookrightarrow \sqrt{2\frac{1}{4}} \hookrightarrow \frac{\pm{3\sqrt{7}}}{\pm{2\sqrt{7}}} \\ \\ \boxed{\pm{1\frac{1}{2}}}

6.) \displaystyle \frac{\sqrt{12}}{\sqrt{48}} \hookrightarrow \sqrt{\frac{1}{4}} \hookrightarrow \frac{\pm{2\sqrt{3}}}{\pm{4\sqrt{3}}} \\ \\ \boxed{\pm{\frac{1}{2}}}

I am joyous to assist you at any time.

5 0
2 years ago
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