They are equal to one another because 4(3+x) can be rewritten using the distributive property as 4(3)+4x or 3+3+3+3+x+x+x+x
The setup boxes in the synthetic division are (b)
<h3>How to determine the setup boxes?</h3>
The dividend is given as:
x^3 + 4x^2 + x - 6
The divisor is given as:
x - 2
Set the divisor to 0
x - 2 = 0
Solve for x
x = 2
Remove the variables in the dividend
1 + 4 + 1 - 6
Remove the arithmetic signs
1 4 1 - 6
So, the setup is:
2 | 1 4 1 - 6
Hence, the setup boxes are (b)
Read more about synthetic division at:
brainly.com/question/12951962
#SPJ1
(x + y)^2 = (x^2 - 2xy + y^2)
First distribute the ^2 on the left side of the equation to each term inside the parenthesis:
x^2+ 2xy + y^2
Now pick one of the variables to solve for and isolate it:
(solving for x)
x^2 + 2xy + y^2 = x^2 - 2xy + y^2
x^2+ 2xy = x^2 - 2xy
2xy = -2xy
-x = x
x = 0
When you solve for y in the equation it will turn out to be 0 as well
To solve the inequality, you need to isolate/get the variable "p" by itself in the inequality:
5p + 26 < 72 Subtract 26 on both sides
5p + 26 - 26 < 72 - 26
5p < 46 Divide 5 on both sides to get "p" by itself
p < 9.2 Your answer is A
