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irakobra [83]
3 years ago
6

Lisa an experienced shipping​ clerk, can fill a certain order in 7 hours. ​bill, a new​ clerk, needs

Mathematics
1 answer:
OLga [1]3 years ago
5 0

Answer:

3.73 hours

Explanation:

In 1 hour, Lisa does 1/7th of the order while Bill does 1/8th of the order in an hour. To find out how long it will take them to fill the order, we have to:

Step 1:

Add the rate of both Lisa and Bill together

1/7 + 1/8

Step 2:

Since both denominators of the fractions are different, you have to find the least common multiple of 7 and 8

7·8= 56    8·7= 56

which is 56.

Step 3:

Then, you have to multiply the numerator of 1/7 with 8 and the numerator of 1/8 with 7.

1·8= 8    1·7= 7

The fractions would now have equal denominators:

Lisa: 8/56    Bill: 7/56

Step 4:

Now, you can add them together

8/56 + 7/56

which equals to 15/56. Both Lisa and Bill together completes 15/56th of the order in 1 hour.

Step 5:

15/56 is not the final answer as it is the RATE of them working together. To find how long it will take them total to complete the order, you must divide 56 with 15.

56/15

which is 3.73 hours in decimal form (rounded).

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PLEASE PEOPLE, HELP ME!! Geometry
Oksanka [162]
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sin(∡B)=[2*A]/[(AB)*(BC)]

we know that
A=5√3
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then

sin(∡B)=[2*5√3]/[(5)*(4)]=10√3/20=√3/2
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c2 = a2 + b2 − 2ab cos(C)

AC²=AB²+BC²-2AB*BC*cos (∡B)

AC²=5²+4²-2*(5)*(4)*cos (60)----------- > 25+16-40*(1/2)=21

AC=√21= 4.58 cms

the answer part 1) is 4.58 cms

2) we know that

a/sinA=b/sin B=c/sinC

and

∡K=α

∡M=β

ME=b

then

b/sin(α)=KE/sin(β)=KM/sin(180-(α+β))

KE=b*sin(β)/sin(α)

A=(1/2)*(ME)*(KE)*sin(180-(α+β))

sin(180-(α+β))=sin(α+β)

A=(1/2)*(b)*(b*sin(β)/sin(α))*sin(α+β)=[(1/2)*b²*sin(β)/sin(α)]*sin(α+β)

A=[(1/2)*b²*sin(β)/sin(α)]*sin(α+β)

KE/sin(β)=KM/sin(180-(α+β))

KM=(KE/sin(β))*sin(180-(α+β))--------- > KM=(KE/sin(β))*sin(α+β)

the answers part 2) are

side KE=b*sin(β)/sin(α)
side KM=(KE/sin(β))*sin(α+β)
Area A=[(1/2)*b²*sin(β)/sin(α)]*sin(α+β)

5 0
3 years ago
What is the probability that a point chosen at random in the given figure will be inside the larger square and outside the small
liraira [26]

Answer:

  • 51/100

Step-by-step explanation:

<em>The probability that a point chosen at random in the given figure will be inside the larger square and outside the smaller square</em> is equal to the ratio of the area of interest to the total area:

<em>P(inside larger square and outside smaller square)</em> = area of interest / total area

<em>P(inside larger square and outside smaller square)</em> = area inside the larger square and outside the smaller square / area of the larger square

<u>Calculations:</u>

<u />

1. <u>Area inside the larger square</u>: side² = (10 cm)² = 100 cm²

2. <u>Area inside the smaller square </u>= side² = (7cm)² = 49 cm²

3. <u>Area inside the larger square and outside the smaller square</u>

  • 100 cm² - 49 cm² = 51 cm²

4.<u> P (inside larger square and outside smaller squere)</u>

  • 51 cm² / 100 cm² = 51/100
5 0
3 years ago
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