Angles on a straight line add up to 180 degrees so
45 + 3x = 180
Subtract 45 from both sides to remove the 45 on the left
3x = 135
Then divide both sides by 3
x = 45
Answer is X = 45
Answer:
1/14x+6
Step-by-step explanation:
I have already learn that
I use the sin rule to find the area
A=(1/2)a*b*sin(∡ab)
1) A=(1/2)*(AB)*(BC)*sin(∡B)
sin(∡B)=[2*A]/[(AB)*(BC)]
we know that
A=5√3
BC=4
AB=5
then
sin(∡B)=[2*5√3]/[(5)*(4)]=10√3/20=√3/2
(∡B)=arc sin (√3/2)= 60°
now i use the the Law of Cosines
c2 = a2 + b2 − 2ab cos(C)
AC²=AB²+BC²-2AB*BC*cos (∡B)
AC²=5²+4²-2*(5)*(4)*cos (60)----------- > 25+16-40*(1/2)=21
AC=√21= 4.58 cms
the answer part 1) is 4.58 cms
2) we know that
a/sinA=b/sin B=c/sinC
and
∡K=α
∡M=β
ME=b
then
b/sin(α)=KE/sin(β)=KM/sin(180-(α+β))
KE=b*sin(β)/sin(α)
A=(1/2)*(ME)*(KE)*sin(180-(α+β))
sin(180-(α+β))=sin(α+β)
A=(1/2)*(b)*(b*sin(β)/sin(α))*sin(α+β)=[(1/2)*b²*sin(β)/sin(α)]*sin(α+β)
A=[(1/2)*b²*sin(β)/sin(α)]*sin(α+β)
KE/sin(β)=KM/sin(180-(α+β))
KM=(KE/sin(β))*sin(180-(α+β))--------- > KM=(KE/sin(β))*sin(α+β)
the answers part 2) areside KE=b*sin(β)/sin(α)side KM=(KE/sin(β))*sin(α+β)Area A=[(1/2)*b²*sin(β)/sin(α)]*sin(α+β)
Answer:
Step-by-step explanation:
<em>The probability that a point chosen at random in the given figure will be inside the larger square and outside the smaller square</em> is equal to the ratio of the area of interest to the total area:
<em>P(inside larger square and outside smaller square)</em> = area of interest / total area
<em>P(inside larger square and outside smaller square)</em> = area inside the larger square and outside the smaller square / area of the larger square
<u>Calculations:</u>
<u />
1. <u>Area inside the larger square</u>: side² = (10 cm)² = 100 cm²
2. <u>Area inside the smaller square </u>= side² = (7cm)² = 49 cm²
3. <u>Area inside the larger square and outside the smaller square</u>
- 100 cm² - 49 cm² = 51 cm²
4.<u> P (inside larger square and outside smaller squere)</u>
- 51 cm² / 100 cm² = 51/100
