Answer:
Yes they will intersect
Function 1= F(X)=2X+5
Function 2=H(X)=3X+2
INTERSECT=(3,11)
Step-by-step explanation:
First of all, we create 2 LINEAR function, i created the function f(x)=2x+5 and the function h(x)=3x+2, both are linear(without a quadratic term). Then
you replace the x for a number:
Table 1 (F(X)=2X+5) Table 2 (H(X)=3X+2)
X=1----->Y=2+5=7 X=1------>Y=3·1+2=5
X=2---->Y=2·2+5=9 X=2----->Y=3·2+2=8
X=3---->Y=3·3+5=11 X=3----->Y=3·3+2=11
With both tables of data we can see that in the X=3/Y=11 point this two linear functions will intersect so the answer is that the two functions will intersect at (3,11)----->(X,Y)
Answer: A) When all three ticket prices generate the same revenue.
Step-by-step explanation:
Reserved tickets cost $20 each.
Field-level tickets cost $50 each.
Seat tickets cost $100 each.
Then if x represents the number of reserved tickets sold, the total revenue for the reserved tickets will be:
R(x) = x*$20
If w represents the number of field-level tickets sold, the total revenue for field-level tickets will be:
F(w) = w*$50
If y represents the number of seat tickets sold, then the total revenue for the seat tickets will be:
S(y) = y*$100
Those equations will intersect when:
R(x) = F(w) = S(y)
This will mean that they will intersect when all three tickets have the same revenue, then the correct option is:
A) When all three ticket prices generate the same revenue.
Answer:
f(−2)=−5
g(2x−1)=−2
Step-by-step explanation:
Answer:
Can you write it again... I dont underestand sorry
The product will be 2x^2 + 5x - 3