Answer:
<h2>210 gaL 60 % Antifreeze II</h2>
Step-by-step explanation:
In the problem, there are two types of antifreeze
antifreeze I and
antifreeze II
antifreeeze I 20 ----70 gal
Antifreeze II 60 ----- x gal
Total 50 ---------------- (70 + x ) gal
20*70+60*x=50(70+x)
1400+60x=3500+50x
60x-50x=3500-1400
10x=2100
x= 210
x=210 gaL 60 % Antifreeze II
the answer is 5
2
9
2
really all you have to do is multiply 126 * 2 * 7 * 3
then all that's next is to just put the letters in the order they were originally at the end of the answer
Answer:
10
Step-by-step explanation:
Answer:
$47,386.44
Step-by-step explanation:
Given;
Dimension of the field = 725 feet by 1,021 feet
Length = 1021 ft
Breadth = 725 ft
Cost per foot = $13.57 per foot
Perimeter of the field = 2 × (length + breadth)
Perimeter = 2 × ( 1021 + 725) = 3492 ft
The cost of fencing the field is;
Cost per feet × perimeter
= $13.57 × 3492
= $47,386.44
