3 years ago

The students in Mr. Nolan's class are writing expressions for the perimeter of a rectangle of side length ? and width w.

1 answer:

6 0

You wanna know witch student is correct?

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kumpel [21]

$r^{2} = 16
r=4
(xh)^{2}2+(y-k)2=(x+1)2 +(y-5)2
h=-1,k=5$

3 0

3 years ago

sashaice [31]

Ans: B=(-3, 7)

Step by step explanation:

7 0

3 years ago

Fofino [41]

No, 243 is not a prime number, it is a composite number.

I hope I helped you again :-)

5 0

4 years ago

Kamila [148]

(17-12) is equal to 5

8 0

3 years ago

Dmitry_Shevchenko [17]

Answer: Option (D) Add the exponents and keep the same base. Then find the reciprocal and change the sign of the exponent.

Explanation:

Given expression:

$(2^3)(2^{-4})$

<em>Step-1: </em>Add the exponents and keep the same base by using $x^a*x^b = x^{a+b}$ property.

$(2^3)(2^{-4}) = 2^{(3+(-4))} = 2^{-1}$

Step-2: The reciprocal of $2^{-1}$ is $\frac{1}{2^{-1}}$ , which is $2^1$

Step-3: The exponent of $2^1$ is +1; therefore, change the sign of exponent. The end expression will now become:

$2^{-1}$

Hence, the correct option is (D) Add the exponents and keep the same base. Then find the reciprocal and change the sign of the exponent.

3 0

4 years ago