Answer:
280 student tickets
520 adult tickets
Explanation:
I'm guessing this is the question you meant to ask:
Eight hundred tickets were sold for a movie production and the receipts for the performance wear $8600. The tickets for adults and students sold for $12.50 and $7.50, respectively. How many of each ticket were sold?
Answer:
If you go to a website with a graph place the points and look where the line sets
Step-by-step explanation:
Answer:
C
Step-by-step explanation:
Both of the y= make upward parabolas
It is also going into the positive direction so it is
<h2>Answer:
y = - ¹/₂ x OR y - 1 = - ¹/₂ (x + 2) </h2>
<h3>Step-by-step explanation: </h3>
For us to write the equation for this line, we need to (1) find the slope of the line, and (2) use one of the points to write an equation:
The question gives us two points, (-2, 1) and (-8, 4), from which we can find the slope and later the equation of the line.
<u>Finding the Slope </u>
The slope of the line (m) = (y₂ - y₁) ÷ (x₂ - x₁)
= (4 - 1) ÷ (-8 - (-2))
= - ¹/₂
<u>Finding the Equation</u>
We can now use the point-slope form (y - y₁) = m(x - x₁)) to write the equation for this line:
⇒ y - 1 = - ¹/₂ (x - (-2))
∴ y - 1 = - ¹/₂ (x + 2)
we could also transform this into the slope-intercept form ( y = mx + c)
since y - 1 = - ¹/₂ (x + 2)
⇒ y = - ¹/₂ x
<em>To test my answer, I have included a Desmos Graph that I graphed using the information provided in the question and my answer.</em>
(1)
Mean length of all fish in the sample - 
<u>Mean</u> = (Sum of observations)/(Number of observations)
= (12 + 5 + 3 + 5 + 8 + 2 + 10 + 9 + 4 + 4)/(10)
= 62/10
=<em> 6.2</em>
(2)
Mean length of adult fish in the sample - 
<u>Mean</u> = (Sum of observations)/(Number of observations)
= (12 + 5 + 8 + 10)/(4)
= 35/4
=<em> 8.75</em>
(3)
Mean length of juvenile fish in the sample - 
<u>Mean</u> = (Sum of observations)/(Number of observations)
= (5 + 3 + 2 + 9 + 4 + 4)/(6)
= 27/6
<em>= 4.5</em>
(4)
Percentage of sample that were adult fish - 
<u>Percentage</u> = (No. of adult fishes)/(Total no. of fishes) × 100
% = (4/10) × 100
<em>% = 40</em>
(5)
Percentage of sample that were juvenile fish - 
<u>Percentage</u> = (No. of juvenile fishes)/(Total no. of fishes) × 100
% = (6/10) × 100
<em>% = </em><em>6</em><em>0</em>
(6)
Percentage of sample that were juveniles over 8 inches long - 
<u>Percentage</u> = (No. of juveniles over 8 inches)/(Total no. of fishes) × 100
% = (1/10) × 100
<em>% = </em><em>1</em><em>0</em>