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3 years ago

(Ill give brainliest, Pls help me! Also, Pls write at least 3 sentences to explain why. Ty :) )

Mathematics

1 answer:

Serjik [45]3 years ago

8 0

Answer: it would be less

Step-by-step explanation: it is less because it is split into more pieces and it is not as big as 67,124

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GEOMETRY HELP!!

Vlada [557]

Answer:

Step-by-step explanation:

To find the coordinate of the midpoint of segment QB, first, find the distance from Q to B.

QB = |4 - 8| = |-4| = 4

The coordinate of the midpoint of QB would be at ½ the distance of QB (½*4 = 2).

Therefore, coordinate of the midpoint of QB = the coordinate of Q + 2 = 4 + 2 = 6

Coordinate of B - 2 = 8 - 2 = 6

Coordinate of the midpoint of QB = 6

Coordinate of W = -8

Coordinate of A = 0

distance from W to A (WA) = |-8 - 0| = |-8| = 8

The coordinate of the midpoint of WA would be at ½ the distance of WA = ½*8 = 4.

Therefore, coordinate of the midpoint of WA = the coordinate of W + 4 = -8 + 4 = -4

Coordinate of A - 4 = 0 - 4 = -4

Coordinate of the midpoint of WA = -4

Now, let's find the midpoint between the two new coordinates we have found, which are -4 and 4

Distance of the segment formed by coordinate -4 and 4 = |-4 - 4| = |-8| = 8

Midpoint = ½*8 = 4

Coordinate of the midpoint = -4 + 4 = 0

4 - 4 = 0

5 0

4 years ago

Four-thirds times the sum of a number and 8 is 24. what is the number?

labwork [276]

So first you take the words and put them into an equation. "a number" that never gets directly told to you will always be a variable, which is easiest to make X. "The sum of a number and 8" will mean that 8+something is the sum so they have to go in parenthesis... giving you
4/3*(x+8)=24
now just solve for X, remembering to use the reverse of PEMDAS, since you're solving for the variable.
remove what is furthest away to the X first.
x+8=24*3/4
x+8=18
x=18-8
x=10
Now, remember to always go through and replace your variable with its value and solve. if it is not equal on both sides, retry the problem because you may have missed a small +, -, or * somewhere!

Hope this helped:)

8 0

3 years ago

Given the following functions f(x) and g(x), solve (f ⋅ g)(3) and select the correct answer below:

Ksenya-84 [330]

I believe you may have the order incorrect. If we were looking at g(f(x)) the answer would be 47. We would get this by sticking the 3 in for x in f(x) and solving, which would give us 48. We would then stick that answer in for x in the g(x), giving us 47.

In its current order the answer would be 28.

6 0

3 years ago

Lucy is going to walk in a fundraising event to raise money for her school band her mother has agreed to donate 7.50$ to the sch

Varvara68 [4.7K]

25=7.50x Lucy walked 3.333 miles

6 0

3 years ago

Use Stokes' Theorem to evaluate S curl F · dS. F(x, y, z) = x2 sin(z)i + y2j + xyk, S is the part of the paraboloid z = 9 − x2 −

Korolek [52]

The vector field

$\vec F(x,y,z)=x^2\sin z\,\vec\imath+y^2\,\vec\jmath+xy\,\vec k$

has curl

$\nabla\times\vec F(x,y,z)=x\,\vec\imath+(x^2\cos z-y)\,\vec\jmath$

Parameterize $S$ by

$\vec s(u,v)=x(u,v)\,\vec\imath+y(u,v)\,\vec\jmath+z(u,v)\,\vec k$

where

$\begin{cases}x(u,v)=u\cos v\\y(u,v)=u\sin v\\z(u,v)=(9-u^2)\end{cases}$

with $0\le u\le3$ and $0\le v\le2\pi$ .

Take the normal vector to $S$ to be

$\dfrac{\partial\vec s}{\partial u}\times\dfrac{\partial\vec s}{\partial v}=2u^2\cos v\,\vec\imath+2u^2\sin v\,\vec\jmath+u\,\vec k$

Then by Stokes' theorem we have

$\displaystyle\int_{\partial S}\vec F\cdot\mathrm d\vec r=\iint_S(\nabla\times\vec F)\cdot\mathrm d\vec S$

$=\displaystyle\int_0^{2\pi}\int_0^3(\nabla\times\vec F)(\vec s(u,v))\cdot\left(\dfrac{\partial\vec s}{\partial u}\times\dfrac{\partial\vec s}{\partial v}\right)\,\mathrm du\,\mathrm dv$

$=\displaystyle\int_0^{2\pi}\int_0^3u^3(2u\cos^3v\sin(u^2-9)+\cos^3v\sin v+2u\sin^3v+\cos v\sin^3v)\,\mathrm du\,\mathrm dv$

which has a value of 0, since each component integral is 0:

$\displaystyle\int_0^{2\pi}\cos^3v\,\mathrm dv=0$

$\displaystyle\int_0^{2\pi}\sin v\cos^3v\,\mathrm dv=0$

$\displaystyle\int_0^{2\pi}\sin^3v\,\mathrm dv=0$

$\displaystyle\int_0^{2\pi}\cos v\sin^3v\,\mathrm dv=0$

4 0

3 years ago