Answer:1.69*10^12 J
Step-by-step explanation:
From figure above, using triangle ratio
485/755.5=y/l. Cross multiplying 485l=755.5y Divide via 485) hence l= 755.5y/485
Consider a slice volume Vslice= (755.5y/485)^2∆y; recall density =150lb/ft^3
Force slice = 150*755.5^2.y^2.∆y/485^2
From figure 2 in the attachment work done for elementary sclice
Wslice= 150.755.5^2.y^2.∆y.(485-y)/485^2
= (150*755.5^2*y^2)(485-y)∆y/485
To calculate the total work we integrate from y=0 to y= 485
Ie W=[ integral of 150*755.5^2 *y^2(485-y)dy/485] at y=0 and y= 485
Integrating the above
W= 150*755.5^2/485[485*y^3/3-y^4/4] at y= 0 and y=485
W= 150*755.5^2/485(485*485^3/3-484^4/4)-(485.0^3/3-0^4/4)
Work done 1.69*10^12joules
The parametric equations seem to describe a circle of radius 3. Its area will be
A = πr² = π·3²
The appropriate choice seems to be
D. 9π
Answer:
No, it is not.
Step-by-step explanation:
comparing the two given values, 1.75 and 6, estimating 1.75 for 6 is not reasonable. This is due to the fact that converting 1.75 to the nearest whole number gives 2 which is far away from 6. Since,
6 - 2 = 4
So, estimating 1.75 for 6 would involve a large value of error. Which make it unreasonable. It would have been more reasonable to estimate 1.75 for 2.
Answer:
The answer would be -7/12
Step-by-step explanation:
Use math.way itll help you tremendously :)
<em></em>Factors of 52 = 1, 2, 4, 13, 26, 52.
The greatest factor of 52 that is a prime number is 13.
