Sin 2A = sinA is true when A=?

Mathematics

1 answer:

strojnjashka [21]3 years ago

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Describe how (2 cubed) (2 superscript negative 4) can be simplified. Multiply the bases and add the exponents. Then find the rec

charle [14.2K]

Add the exponents and keep the same base. Then reciprocal it and change the sign of the exponent. Then the value of the exponent expression is 0.5.

<h3>What is an exponent?</h3>

Exponential notation is the form of mathematical shorthand which allows us to write complicated expressions more succinctly. An exponent is a number or letter is called the base. It indicates that the base is to raise to a certain power. X is the base and n is the power.

The exponent expression is 2³ × 2⁻⁴ can be simplified.

Add the exponents and keep the same base. Then we have

2³ × 2⁻⁴ = 2⁽³⁻⁴⁾

2³ × 2⁻⁴ = 2⁻¹

Then find the reciprocal and change the sign of the exponent.

$2^3* 2^{-4} = 2^{-1}\\\\2^3* 2^{-4} = \dfrac{1}{2}\\\\2^3* 2^{-4} = 0.5$

The value is 0.5.

More about the exponent link is given below.

brainly.com/question/5497425

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2 years ago

Consider the expression 2√3 cos(x)csc(x)+4cos(x)-3csc(x)-2 √ 3 This expression can be represented as the product of the factors.

Alla [95]

Answer with explanation:

The given expression is:

$2 \sqrt{3}\cos x * \csc x+4 \cos x-3 \csc x-2\sqrt{3}\\\\=2 \cos x*(\sqrt{3}*\csc x+2)-\sqrt{3}*(\sqrt{3}*\csc x+2)\\\\\rightarrow (2\cos x -\sqrt{3})*(\sqrt{3}*\csc x+2)\\\\\rightarrow (2\cos x -\sqrt{3})*(\sqrt{3}*\csc x+2)=0\\\\(2\cos x -\sqrt{3})=0 \wedge (\sqrt{3}*\csc x+2)=0$

$\cos x=\frac{\sqrt{3}}{2} \wedge \csc x=\frac{-2}{\sqrt{3}}\\\\x=\frac{\pi}{6},2\pi-\frac{\pi}{6}\\\\x=\frac{\pi}{6},\frac{11\pi}{6} \wedge x=\pi+\frac{\pi}{3} ,2\pi-\frac{\pi}{3}\\\\x=\frac{4\pi}{3},\frac{5\pi}{3}\\\\x={\frac{\pi}{6},\frac{11\pi}{6},\frac{4\pi}{3},\frac{5\pi}{3}}$