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IRISSAK [1]
3 years ago
9

Find the value of x in the triangle.

Mathematics
1 answer:
Studentka2010 [4]3 years ago
5 0

Answer:

164

Step-by-step explanation:

Remember, everytriangle is 180 all together. So add what you see and subtract it from 180.

9+7= 16

180-16= 164

Hope it helps

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I need the middle one
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8

Step-by-step explanation:

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4 years ago
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Point B has coordinates ​(4,1). The​ x-coordinate of point A is -4. The distance between point A and point B is 10 units. What a
klasskru [66]

Given:

Point B has coordinates ​(4,1).

The​ x-coordinate of point A is -4.

The distance between point A and point B is 10 units.

To find:

The possible coordinates of point​ A.

Solution:

Let the y-coordinate of point A be y. Then the two points are A(-4,y) and B(4,1).

Distance formula:

D=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

The distance between point A and point B is 10 units.

\sqrt{(4-(-4))^2+(1-y)^2}=10

Taking square on both sides, we get

(8)^2+(1-y)^2=100

(1-y)^2=100-64

(1-y)^2=36

Taking square root on both sides, we get

(1-y)=\pm \sqrt{36}

-y=\pm 6-1

y=1\mp 6

y=1-6 and y=1+6

y=-5 and y=7

Therefore, the possible coordinates of point​ A are either (-4,-5) or (-4,7).

7 0
3 years ago
  What values for θ (0 ≤ θ ≤ 2pie ) satisfy the equation? 
svetoff [14.1K]
Factor out the cos<span>θ:
</span>cosθ (2sin<span>θ + sqrt3) = 0
</span>Therefore, the only ways this can happen are if either cosθ = 0 or if (2sin<span>θ + sqrt3) = 0
</span>The first case, cosθ = 0 only at θ <span>= pi/2, 3pi/2.
</span>The second case, <span>(2sin<span>θ + sqrt3) = 0 simplifies to:
</span></span>sin<span>θ = (-sqrt3)/2
</span><span><span>θ = 4pi/3, 5pi/3
</span></span><span><span>Therefore the answer is A.
</span></span>
7 0
4 years ago
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