Answer:
x = ±√37/9
Step-by-step explanation:
x² = 37/81
√(x²) = √(37/81)
x = ± √(37)/√(81)
x = ± √37/9
Imx->0 (asin2x + b log(cosx))/x4 = 1/2 [0/0 form] ,applying L'Hospital rule ,we get
= > limx->0 (2a*sinx*cosx - (b /cosx)*sinx)/ 4x3 = 1/2 => limx->0 (a*sin2x - b*tanx)/ 4x3 = 1/2 [0/0 form],
applying L'Hospital rule again ,we get,
= > limx->0 (2a*cos2x - b*sec2x) / 12x2 = 1/2
For above limit to exist,Numerator must be zero so that we get [0/0 form] & we can further proceed.
Hence 2a - b =0 => 2a = b ------(A)
limx->0 (b*cos2x - b*sec2x) / 12x2 = 1/2 [0/0 form], applying L'Hospital rule again ,we get,
= > limx->0 b*(-2sin2x - 2secx*secx.tanx) / 24x = 1/2 => limx->0 2b*[-sin2x - (1+tan2x)tanx] / 24x = 1/2
[0/0 form], applying L'Hospital rule again ,we get,
limx->0 2b*[-2cos2x - (sec2x+3tan2x*sec2x)] / 24 = 1/2 = > 2b[-2 -1] / 24 = 1/2 => -6b/24 = 1/2 => b = -2
from (A), we have , 2a = b => 2a = -2 => a = -1
Hence a =-1 & b = -2
X=4 and y= -3 Hope it helps
Question:
Can 25/12 be simplified?
Answer:
No, it cannot be simplified because 25 is an odd number and 12 is an even number.
Hope this helped!!
Let s = the smaller one of the two.
Since they are consecutive, the second one is (s + 1)
Since they are natural numbers, they cannot be negative.
We know that s(s + 1) = s + (s + 1) + 155
So:
s(s + 1) = 2s + 156
s^2 + s = 2s + 156
s^2 - s - 156 = 0
(s - 13)(s + 12) = 0
From this, it looks like s can be either 13 or -12. But since it's a natural number, it cannot be negative. So, it is 13.
s was the smaller one. The larger one is s + 1 = 14
Check: 13*14=182=13+14+155
