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Hatshy [7]
2 years ago
9

18m+42n in distributive property

Mathematics
2 answers:
chubhunter [2.5K]2 years ago
8 0

Adnswer:

18m+42n in distributive property=6(3m+7n)

Step-by-step explanation:

34kurt2 years ago
5 0

Answer and Step-by-step explanation:

The answer to this expression would be 6(3m + 7n).

18m + 42n is the distributive version of the same expression.

To un-distribute, you would find the greatest common factor of both numbers, and pull it out of the expression.

18 and 42 have a greatest common factor of 6.

18 divided by 6 is 3.

42 divided by 6 is 7.

<u>That leaves us with 6(3m + 7n).</u>

<u></u>

<em><u>#teamtrees #PAW (Plant And Water)</u></em>

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Solve for x..........10 points*
Ivanshal [37]

Answer:

\huge\boxed{\sf x = 12}

Step-by-step explanation:

8x + 34 = 130 <u>(Vertical Angles are Equal)</u>

Subtract 34 to both sides

8x = 130 - 34

8x = 96

Divide both sides by 8

x = 96 / 8

x = 12

\rule[225]{225}{2}

Hope this helped!

<h3>~AH1807</h3>
3 0
3 years ago
Read 2 more answers
Solve this function f(-4)= -3x+6
timama [110]

Answer:

Solve for f.

f(−4)=−3x+6

Step 1: Divide both sides by -4.

−4f/-4 = −3x+6/−4

f=3/4x + −3/2

Answer:

f= 3/4x + −3/2

7 0
3 years ago
the sum of 2 consecutive integers is at most the difference between nine times the smaller and 5 times the larger
Reil [10]
<h2>Answer:</h2>

x\geq 3 \ and \ x+1 \geq 4

<h2>Step-by-step explanation:</h2>

The question in this problem is:

<em>The sum of 2 consecutive integers is at most the difference between nine times the smaller and 5 times the larger. What are the numbers?</em>

<em />

First of all, let's name the first variable x which is the smaller number. Accordingly, the lager number will be x+1 given that those numbers are consecutive. On the other hand<em> at most </em>conveys the idea of an inequality, which is:

\leq \\ which \ means \ less \ than

So:

1. The sum of 2 consecutive integers can be written as:

v+(v+1)

2. Nine times the smaller and 5 times the larger can be written as:

9v-5(v+1)

Finally, the whole statement:

The sum of 2 consecutive integers is at most the difference between nine times the smaller and 5 times the larger:

x+(x+1) \leq 9x-5(x+1) \\ \\ x+x+1\leq 9x-5x-5 \\ \\ 2x+1 \leq 4x-5 \\ \\ 6 \leq 2x \\ \\

x+(x+1) \leq 9x-5(x+1) \\ \\ x+x+1\leq 9x-5x-5 \\ \\ 2x+1 \leq 4x-5 \\ \\ 6 \leq 2x \\ \\ \frac{6}{2} \leq \frac{2x}{2} \\ \\ 3 \leq x \\ \\ x\geq 3 \\ \\ and \\ \\ x+1 \geq 4

The two numbers are:

x\geq 3 \ and \ x+1 \geq 4

6 0
3 years ago
PLEASE HELP <br> ANSWER ASAP
VLD [36.1K]
Question 1: h+4= how many kids in history class.
I think this cause it says to represent the # of kids in the English class with the varible h. there are 4 more kids in the history class for you just add four to the English class( h). this may be wrong tho

question 2: 57+4= 61.

you just input the 57 where the h (# of kids in English class) cause it need to figure out how many are in history and their are just four more kids. I think


also sorry if I suck at explaining things, this makes sorta sense
7 0
3 years ago
Select the correct answer from each drop-down menu. if f(x)=x^2+2x-3 and g(x)=x^2-9, find (f/g)(4) and (f+g)(4).
Nataly_w [17]

Answer:

(f/g)(4) = 3

(f + g)(4) = 28

Step-by-step explanation:

(f/g) = \frac{x^2+2x-3}{x^2-9}

(f + g) = 2x^2 + 2x -12

Simply plug in 4 for x in both equations to find you answer!

3 0
3 years ago
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