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Savatey [412]
3 years ago
9

What does an atomic emission spectrum look like if the electrons energy levels in an atom were not quantizied

Chemistry
1 answer:
balandron [24]3 years ago
8 0

Answer:

b

Explanation:

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The following are properties of compounds _____.
zloy xaker [14]

Answer is D. that is all of the above.

Elements are chemically joined to form compounds and every compound have unique property that helps to identify it. Compounds have different kind of properties that are unique for a particular compound that is boiling point, vapour pressure and density that provides it a unique characteristics. So the answer here will be D. that is all of the above.

5 0
4 years ago
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Apart from boiling point and flammability, what other quality does the size of the molecules in hydrocarbons affect?​
Sonbull [250]

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Viscosity

Explanation:

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3 years ago
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In the following reaction, what is the effect of adding more NO2 to the starting reaction mixture?
Mars2501 [29]

Answer:

It would increase the final quantity of products

Explanation:

According to the Le- Chatelier principle,

At equilibrium state when stress is applied to the system, the system will behave in such a way to nullify the stress.

The equilibrium can be disturb,

By changing the concentration

By changing the volume

By changing the pressure

By changing the temperature

Consider the following chemical reaction.

Chemical reaction:

2NO₂ ⇄ N₂O₄

In this reaction the equilibrium is disturb by increasing the concentration of reactant.

When the concentration of reactant is increased the system will proceed in forward direction in order to regain the equilibrium. Because when reactant concentration is high it means reaction is not on equilibrium state. As the concentration of NO₂ increased the reaction proceed in forward direction to regain the equilibrium state and more product is formed.

5 0
3 years ago
What is Ka for H2CO3(aq)=H (aq0 HCO3-(aq)
horrorfan [7]
The Ka for H_2CO_3=H^++HCO_3^- is approximately 10^{-3.6}
6 0
4 years ago
If 832J of energy is required to raise the temperature of a sample of aluminum from 20.0° C to 97.0° C, what mass is the sample
LiRa [457]
Data:
Q (Amount of heat) = 832 J
m (mass) = ?
c (Specific heat) = <span>0.90 J/(g × ° C)
T (final) = 97 ºC
To (initial) = 20 ºC
</span>ΔT = T - To → ΔT = 97 - 20 → ΔT = 77 ºC

Formula:
Q = m*c*ΔT

Solving:
Q = m*c*ΔT
832 = m*0.90*77
832 = 69.3m
69.3m = 832
m =  \frac{832}{69.3}
\boxed{\boxed{m \approx 12.00\:g}}\end{array}}\qquad\quad\checkmark
5 0
3 years ago
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