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Ratling [72]
2 years ago
13

In the following experiment, a coffee-cup calorimeter containing 100mL OF H2O is used.

Chemistry
1 answer:
bearhunter [10]2 years ago
5 0

Please provide more of the question so I am able to answer, but I do know that H20 has 0 calories.

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Air trapped in a cylinder fitted with a piston occupies 145.7 mL at 1.08 atm pressure. What is the new volume when the piston is
Anon25 [30]

The new volume of air trapper in the cylinder is determined as 116.56 mL.

<h3>New volume of air in the cylinder</h3>

The volume of air trapper in the cylinder is determined from Boyle's law;

P₁V₁ = P₂V₂

where;

  • P₁ is initial pressure = 1.08 atm
  • V₁ is initial volume = 145.7 mL
  • P₂ is new pressure = 1.25 x 1.08 atm = 1.35 atm
  • V₂ is new volume = ?

V₂ = (P₁V₁)/P₂

V₂ = (1.08 x 145.7)/1.35

V₂ = 116.56 mL

Thus, the new volume of air trapper in the cylinder is determined as 116.56 mL.

Learn more about volume here: brainly.com/question/1972490

#SPJ1

6 0
2 years ago
A(n)____ is a negatively-charged subatomic particle.<br> Help plz I need this before tmr morning
katrin [286]

the answer is electron

6 0
4 years ago
Select the mixture which is capable of tolerating addition of a strong acid without altering the pH? a.) 1.0 M HCl, 1.0 M NaCl b
wlad13 [49]

Answer:

d.) 1.0 M HNO2, 1.0 M NaNO2

Explanation:

A buffer is a mixture that is capable of tolerating addition of a strong acid or base without altering the pH substantially.

A buffer is the mixture of a <em>WEAK ACID AND ITS CONJUGATE BASE </em>or a <em>WEAK BASE AND ITS CONJUGATE ACID</em>

<em></em>

In the problems:

a) HCl is a strong acid and NaCl a salt. NO buffer

b) NH3 is a weak base and NaCL a salt. NO buffer

c) HF is a weak acid and NaCl a salt. NO buffer.

<h3>d) HNO2 is a weak acid and NaNO2 its conjugate base. A BUFFER</h3>
7 0
3 years ago
Is the group number the number of electrons on the outermost shell ​
vagabundo [1.1K]
In the column have the same electrons on the outer shell. Which the outer shell electrons are call valence electrons.
6 0
3 years ago
What mass of sulfur has to burn to produce 4.5l so2 at 300°c and 101kpa s(s) o2(<br> g. so2(<br> g.?
Mandarinka [93]
S + O2 --> So2. P = 101kPa = 1atm. R = 0.082 atm - L - (mol-K)^-1. Applying ideal gas equation PV = nRT. n = 1x4.5/0.082x573 = 0.096mole. According to stoichiometry, moles of S = moles of SO2 = 0.096mol. Mass of S = moles of So2 x molar Wt = 0.095x32 = 3.04moles. Hope it helps
8 0
3 years ago
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