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Ratling [72]
2 years ago
13

In the following experiment, a coffee-cup calorimeter containing 100mL OF H2O is used.

Chemistry
1 answer:
bearhunter [10]2 years ago
5 0

Please provide more of the question so I am able to answer, but I do know that H20 has 0 calories.

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How many grams of tin would occupy 5.5 L if it had a density of 7.265
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In order to find the mass of tin with the given volume of 5.5 L and density of 7.265, we will use the formula
Density = Mass / Volume

We will just multiply both sides of the equation by the volume and we will get:
Mass = Volume x Density

We can now solve the problem by substituting the given.

Mass = 5.5 L x 7.265 g/L
Mass = 39.96 g

Answer: there are 39.96 grams of tin

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3 years ago
25.4 g of salt was dissolved in distilled water to make 425 mL of solution.
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Before any reaction occurs, the concentration of A in the reaction below is 0.0510 M. What is the equilibrium constant if the co
Lilit [14]

Answer:

0.0119

Explanation:

There was a part missing. I think this is the whole question:

<em>Before any reaction occurs, the concentration of A in the reaction below is 0.0510 M. What is the equilibrium constant if the concentration of A at equilibrium is 0.0153 M?</em>

A (aq) ⇌ 2B (aq) + C(aq)

<em>Remember to use correct significant figures in your answer. Do not include units in your response.</em>

First, we have to make an ICE Chart, which stands for initial, change and equilibrium. We will call "x" unknown concentrations.

        A (aq) ⇌ 2B (aq) + C (aq)

I       0.0510       0            0

C         -x          +2x          +x

E    0.0510-x     2x            x

Since the concentration at equilibrium of A is 0.0153 M, we get

0.0510 - x = 0.0153 \\x = 0.0357

We can use the value of x to calculate the concentrations at equilibrium.

[A]e = 0.0153 M \\[B]e = 2x = 2(0.0357) = 0.0714 M \\[C]e = x = 0.0357 M \\

The equilibrium constant, Kc, is the ratio of the equilibrium concentrations of products over the equilibrium concentrations of reactants each raised to the power of their stoichiometric coefficients.

Kc = \frac{[B]^{2}  \times [C]}{[A]} = \frac{0.0714^{2}  \times 0.0357}{0.0153} = 0.0119

The equilibrium constant for this reaction at equilibrium is 0.0119.

You can learn more about equilibrium here: brainly.com/question/4289021

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2 years ago
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