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Alex73 [517]
3 years ago
7

NASA helps fund science education

Chemistry
2 answers:
Jlenok [28]3 years ago
5 0

Answer:

"People with more knowledge of science are always healthier"

Explanation:

zvonat [6]3 years ago
3 0

Answer:

What are the options

Explanation:

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answer last one “How many moles of hydrogen are consumed to produce 100 g ammonia” ? explanation and answer required then u get
SVETLANKA909090 [29]

Answer:

The answer is 17.03052. We assume you are converting between grams Ammonia and mole.

4 0
3 years ago
Clear glass, water, and air are examples of what kind of material?
irina1246 [14]

Clear glass, water, and air are examples of transparent material. They can be seen through with no extra factors or complications. Therefore, your answer would be D. transparent.

6 0
4 years ago
Read 2 more answers
When an electron in an atom jumps from a high-energy orbital to a lower-energy one, what happens??
Burka [1]
All the energy gets released i think
8 0
4 years ago
In some types of alcohol digestion, alcohol C_2 H_5 OHC 2 ​ H 5 ​ OHC, start subscript, 2, end subscript, H, start subscript, 5,
kari74 [83]

Answer:

This is the typical route of alcohol metabolism, where in the liver it is first transformed to acetaldehyde and then to acetate.

Explanation:

Ethanol is not digested but absorbed and follows its metabolic pathway in the liver, producing in the first instance acetaldehyde, which is the main substance that causes the hangover and then this compound is transformed into the final product, which is acetate Later acetate is metabolized to Acetyl-CoA. The enzyme responsible for the metabolism of ethanol is alcohol dehydrogenase in the liver, and for the cytochrome P-450 dependent system and for catalase in the liver.

3 0
3 years ago
How would I Determine the number of moles in 3.51 x 10^23 formula units of CaCl2
Andrej [43]

Answer:

by using this formula you will get it

Explanation:

number of mole = number of particles÷ Avogadro's number

n=3.51×10^23÷ 6.02×10^23

n = 0.58 moles

8 0
3 years ago
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