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3 years ago

Can somebody please help me bc im so lost its ridiculous

Mathematics

2 answers:

PSYCHO15rus [73]3 years ago

8 0

Answer:

1) 120° 2) 98° 3) 104° 4) 140°

Step-by-step explanation:

1) add the two angles together then set them equal to 180 then solve for x. Once x is found plug it in for ∠A

2) set the two angles equal to each other then solve for x. once x is found plug it in for ∠B

3) set the two angles equal to each other to find x. once x is found plug it in for ∠C

4) add the two angles together then set it equal to 180. solve for x. once x is fould plug it in for ∠D

kodGreya [7K]3 years ago

4 0

Answer:

1. A = 120

2. B = 98

3. C = 86

4. D = 176

Step-by-step explanation:

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alexdok [17]

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4 years ago

Read 2 more answers

simplify 5ab+9a-ab-7a and justify each step as associative , distributive, commutative, or additive property.

Vladimir [108]

Answer:

5ab-ab+9a-7a

ab(5-1)+a(9-7)

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a(4b+2)

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3 years ago

Is y=-3 a linear equation?

Stels [109]

If degree of variable is one then eq. is linear
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3 years ago

Based on a study of population projections for 2000 to 2050, the projected population of a group of people (in millions) can b

Olegator [25]

Answer:

(a) 0.107 million per year

(b) 0.114 million per year

Step-by-step explanation:

$A(t) = 11.19(1.009)^t$

(a) The average rate of change between 2000 and 2014 is determined by dividing the difference in the populations in the two years by the number of years. In the year 2000, $t=0$ and in 2014, $t=14$ . Mathematically,

$\text{Rate}=\dfrac{A(2014) - A(2000)}{2014-2000}=\dfrac{11.19(1.009)^14-11.19(1.009)^0} {14}$

$A(0)=\dfrac{12.69-11.19}{14}=\dfrac{1.5}{14}=0.107$

(b) The instantaneous rate of change is determined by finding the differential derivative at that year.

The result of differentiating functions of the firm $y=a^x$ (where $a$ is a constant) is $\dfrac{dy}{dx}=a^x\ln a$ . Let's use in this in finding the derivative of $A(t)$ .

$A\prime(t) = \dfrac{A}{t}=11.19\cdot1.009^t\ln1.009$

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$A\prime(14) =11.19\cdot1.009^14\ln1.009=0.114$

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3 years ago

find real numbers a, b, and c so that the graph of the function y=ax^2+c contains the points (-1,6), (2,7), and (0,1)

Paraphin [41]

This gives you three simultaneous equations:

6 = a + c
7 = 4a + c
1 = c

c = 1

If c =1,

6 = a + 1
a = 5

This doesn't work in the second equation, so the quadratic that goes through these points is not in the form y = ax^2 + bx + c
Was there supposed to be a b in the equation?

5 0

4 years ago