All categories

2 years ago

4 thousands less than 1.895

Mathematics

2 answers:

solmaris [256]2 years ago

8 0

Answer:

You mean thousandths?

It’s 1.891

Step-by-step explanation:

The thousandths place is the 3rd digit to the right of the decimal. 5-4=1

zimovet [89]2 years ago

7 0

Answer:

1.891

Step-by-step explanation:

Look to picture for further explanation

Hope this helps :)

You might be interested in

Suiting at 6 a.m., cars, buses, and motorcycles arrive at a highway loll booth according to independent Poisson processes. Cars

dem82 [27]

Answer:

Step-by-step explanation:

From the information given:

the rate of the cars = $\dfrac{1}{5} \ car / min = 0.2 \ car /min$

the rate of the buses = $\dfrac{1}{10} \ bus / min = 0.1 \ bus /min$

the rate of motorcycle = $\dfrac{1}{30} \ motorcycle / min = 0.0333 \ motorcycle /min$

The probability of any event at a given time t can be expressed as:

$P(event \ (x) \ in \ time \ (t)\ min) = \dfrac{e^{-rate \times t}\times (rate \times t)^x}{x!}$

∴

(a)

$P(2 \ car \ in \ 20 \ min) = \dfrac{e^{-0.20\times 20}\times (0.2 \times 20)^2}{2!}$

$P(2 \ car \ in \ 20 \ min) =0.1465$

$P ( 1 \ motorcycle \ in \ 20 \ min) = \dfrac{e^{-0.0333\times 20}\times (0.0333 \times 20)^1}{1!}$

$P ( 1 \ motorcycle \ in \ 20 \ min) = 0.3422$

$P ( 0 \ buses \ in \ 20 \ min) = \dfrac{e^{-0.1\times 20}\times (0.1 \times 20)^0}{0!}$

$P ( 0 \ buses \ in \ 20 \ min) = 0.1353$

Thus;

P(exactly 2 cars, 1 motorcycle in 20 minutes) = 0.1465 × 0.3422 × 0.1353

P(exactly 2 cars, 1 motorcycle in 20 minutes) = 0.0068

(b)

the rate of the total vehicles = 0.2 + 0.1 + 0.0333 = 0.3333

the rate of vehicles with exact change = rate of total vehicles × P(exact change)

$= 0.3333 \times \dfrac{1}{4}$

= 0.0833

∴

$P(zero \ exact \ change \ in \ 10 minutes) = \dfrac{e^{-0.0833\times 10}\times (0.0833 \times 10)^0}{0!}$

P(zero exact change in 10 minutes) = 0.4347

The probability of the 7th motorcycle after the arrival of the third motorcycle is:

$P( 4 \ motorcyles \ in \ 45 \ minutes) =\dfrac{e^{-0.0333\times 45}\times (0.0333 \times 45)^4}{4!}$

$P( 4 \ motorcyles \ in \ 45 \ minutes) =0.0469$

Thus; the probability of the 7th motorcycle after the arrival of the third one is = 0.0469

P(at least one other vehicle arrives between 3rd and 4th car arrival)

= 1 - P(no other vehicle arrives between 3rd and 4th car arrival)

The 3rd car arrives at 15 minutes

The 4th car arrives at 20 minutes

The interval between the two = 5 minutes

<u>For Bus:</u>

P(no other vehicle other vehicle arrives within 5 minutes is)

= $\dfrac{6}{12} = 0.5$

<u>For motorcycle:</u>

$= \dfrac{2 }{12} = \dfrac{1 }{6}$

∴

The required probability = $1 - \Bigg ( \dfrac{e^{-0.5 \times 0.5^0}}{0!} \times \dfrac{e^{-1/6}\times (1/6)^0}{0!} \Bigg)$

= 1- 0.5134

= 0.4866

6 0

2 years ago

What is negative five plus negative four bracketed

Brrunno [24]

-5+(-4)

-5-4

-9

Therefore, -9 is the correct answer

8 0

2 years ago

There are 11 books on a shelf. 3 of these books are new. The rest of them are used.

antiseptic1488 [7]

Sooo , 8? Is there more to the question

4 0

2 years ago

Cindy had 13 stickers. She bought 18 stickers from a store in the mall and got 5 stickers for her birthday. Then Cindy gave 8 of

AlexFokin [52]

Answer:

18 stickers.

Step-by-step explanation:

Cindy buys 18 more stickers in the start. This results in 13+18= 31 stickers. She then gets five for her birthday. 31+5=36 so she now has 36 stickers but she then gives eight away which means she has 36-8=28 stickers. She uses ten stickers to decorate so Cindy has 28-10=18 stickers left

8 0

3 years ago

Read 2 more answers

The square of a number is 3 less than four times the number. which values could be the number?

Lina20 [59]

Answer:

x could be 3 or 1

Step-by-step explanation:

x²+3=4x

x²-4x+3=0

(x-3)(x-1)

x could be 3 or 1

5 0

2 years ago

Read 2 more answers

4 thousands less than 1.895​

4 thousands less than 1.895