A rocket is launched from a tower. The height of the rocket, y in feet, is rel
1 answer:
9514 1404 393
Answer:
9.70 seconds
Step-by-step explanation:
The zero of the equation can be found using the quadratic formula.
ax² +bx +c = 0
x = (-b ±√(b² -4ac))/(2a)
We are only interested in the positive value of x, so this will be ...
x = (-147 -√(147² -4(-16)(80)))/(2(-16)) = (147 +√2679)/32
x ≈ 9.7028 ≈ 9.70 . . . . seconds
The rocket will hit the ground after about 9.70 seconds.
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