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2 years ago

Which of these is an disadvantage of CT scan te

Mathematics

1 answer:

Semmy [17]2 years ago

8 0

Answer:

It cannot be used to assess individual renal function or degree of obstruction. Sulfadiazine stones are also difficult to visualize on CT because of relatively low attenuation. It is relatively expensive.

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A cyclist rode the first 30-mile portion of his workout at a constant speed. For the 24-mile cooldown portion of his workout, he

LuckyWell [14K]

what math is this could you tell me what math this is plz

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2 years ago

Question 18 (5 points)

Bas_tet [7]

Answer: A growing division of labor between employees with different skills

Step-by-step explanation:

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1 year ago

How do I find the diameter and circumference when given the area?

JulijaS [17]

Hello from MrBillDoesMath!

Answer:

Diameter = 2r = 2 (sqrt(24/Pi))

Circumference = 4 sqrt(6Pi)

Discussion:

Given:

Area of circle = Pi r^2

24 = Pi r^2 => (as Pi r^2 is the formula for area of a circle)

24/Pi = r^2 => ( now take the square root of both sides)

r= sqrt(24/Pi)

Diameter = 2r = 2 (sqrt(24/Pi))

Circumference = 2 PI r = 2Pi (sqrt(24/Pi))

= 2Pi (sqrt(24)/sqrt(Pi) )

= 2Pi (2sqrt(6)/sqrt(Pi) )

= 4 (pi/ sqrt(Pi) ) sqrt(6)

= 4 sqrt(Pi) sqrt(6)

= 4 sqrt(6Pi)

Thank you,

MrB

6 0

3 years ago

The answer to this question HELP ME PLS

Papessa [141]

The answer is a because 552.50 x .12 is 66.30. 66.30 minus 552.50 is 486.50 and that divided by 7 is 69.45

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3 years ago

Section 5.2 Problem 17:

Elina [12.6K]

This DE has characteristic equation

$4r^2 - 12r + 9r = (2r - 3)^2 = 0$

with a repeated root at r = 3/2. Then the characteristic solution is

$y_c = C_1 e^{\frac32 x} + C_2 x e^{\frac32 x}$

which has derivative

${y_c}' = \dfrac{3C_1}2 e^{\frac32 x} + \dfrac{3C_2}2 x e^{\frac32x} + C_2 e^{\frac32 x}$

Use the given initial conditions to solve for the constants:

$y(0) = 3 \implies 3 = C_1$

$y'(0) = \dfrac52 \implies \dfrac52 = \dfrac{3C_1}2 + C_2 \implies C_2 = -2$

and so the particular solution to the IVP is

$\boxed{y(x) = 3 e^{\frac32 x} - 2 x e^{\frac32 x}}$

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2 years ago