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KonstantinChe [14]
2 years ago
13

Which of these is an disadvantage of CT scan te

Mathematics
1 answer:
Semmy [17]2 years ago
8 0

Answer:

It cannot be used to assess individual renal function or degree of obstruction. Sulfadiazine stones are also difficult to visualize on CT because of relatively low attenuation. It is relatively expensive.

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How do I find the diameter and circumference when given the area?
JulijaS [17]

Hello from MrBillDoesMath!

Answer:

Diameter = 2r = 2 (sqrt(24/Pi))

Circumference =  4 sqrt(6Pi)


Discussion:

Given:

     Area  of circle =  Pi r^2

               24 = Pi r^2        =>  (as Pi r^2 is the formula for area of a circle)

               24/Pi = r^2       =>  ( now take the square root of both sides)

               r= sqrt(24/Pi)


Diameter = 2r = 2 (sqrt(24/Pi))

Circumference = 2 PI r = 2Pi (sqrt(24/Pi))

                                       = 2Pi (sqrt(24)/sqrt(Pi) )

                                       = 2Pi (2sqrt(6)/sqrt(Pi) )

                                       =  4 (pi/ sqrt(Pi) ) sqrt(6)

                                       = 4 sqrt(Pi) sqrt(6)

                                       = 4 sqrt(6Pi)


Thank you,

MrB

6 0
3 years ago
The answer to this question HELP ME PLS
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The answer is a because 552.50 x .12 is 66.30. 66.30 minus 552.50 is 486.50 and that divided by 7 is 69.45

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3 years ago
Section 5.2 Problem 17:
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This DE has characteristic equation

4r^2 - 12r + 9r = (2r - 3)^2 = 0

with a repeated root at r = 3/2. Then the characteristic solution is

y_c = C_1 e^{\frac32 x} + C_2 x e^{\frac32 x}

which has derivative

{y_c}' = \dfrac{3C_1}2 e^{\frac32 x} + \dfrac{3C_2}2 x e^{\frac32x} + C_2 e^{\frac32 x}

Use the given initial conditions to solve for the constants:

y(0) = 3 \implies 3 = C_1

y'(0) = \dfrac52 \implies \dfrac52 = \dfrac{3C_1}2 + C_2 \implies C_2 = -2

and so the particular solution to the IVP is

\boxed{y(x) = 3 e^{\frac32 x} - 2 x e^{\frac32 x}}

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