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Rainbow [258]
3 years ago
14

5+5=−10 1.p=1 2.p=3 3.p= -3 4.p= -1

Mathematics
1 answer:
Black_prince [1.1K]3 years ago
6 0
The answer is 1

thank me later
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I need help plish k squared minus 11
timama [110]

Answer:  It's an algebraic expression

Step-by-step explanation:  k²- 11 is an algebraic expression.

If you found my answer helpful please choose my answer as Brainliest. I would appreciate it! Good luck everyone! :)

8 0
2 years ago
2(x-8) + 4x = 6(x - 2) - 4
mrs_skeptik [129]
0=0, all numbers are solutions
5 0
3 years ago
Read 2 more answers
I watched a video and didn't get my free answer, can I have some help,
vazorg [7]

Answer:

y + 13 = 5(x + 2)

Step-by-step explanation:

The slope-intercept form of the equation of a line is

y = mx + b,

where m = slope, and b = y-intercept.

From the slope-intercept equation y = 5x - 3, we see that the slope of the line is 3.

The point-slope form of the equation of a line is:

y - y1 = m(x - x1)

where m = slope, and (x1, y1) is a point on the line.

We have point (-2, -13), so x1 = -2, and y1 = -13.

We also have slope 5, so m = 5.

Now we use the coordinates of the given point and the slope in the point-slope equation.

y - (-13) = 5(x - (-2))

We simplify to get

y + 13 = 5(x + 2)

8 0
2 years ago
Pleaseeee helpppppppppp
o-na [289]

Answer:

25 ft^2

Step-by-step explanation:

In direct variation, if y varies directly with x, then the equation has the form

y = kx,

where k is the constant of proportionality. y is proportional to x.

Let's call the area y and the distance x.

Here, the area varies with the square of the distance, so the equation has the form

y = kx^2

Here, y is proportional to the square of x.

We can find the value of k by using the given information.

y = kx^2

When x = 20 ft, y = 16 ft^2.

16 = k(20^2)

k = 16/400

k = 1/25

The equation of the relation is:

y = (1/25)x^2

Now we use the equation we found to answer the question.

What is y (the area) when x (the distance) is 25 ft?

y = (1/25)x^2

y = (1/25)(25^2)

y = 25

Answer: 25 ft^2

5 0
2 years ago
One serving of Mike’s crackers has 150 calories and a mass of 30 grams. How many calories are in 6 grams of the crackers?
Elodia [21]
\bf \begin{array}{ccll}
calories&grams\\
\text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\
150&30\\
c&6
\end{array}\implies \cfrac{150}{c}=\cfrac{30}{6}\implies \cfrac{150\cdot 6}{30}=c
3 0
3 years ago
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