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Sliva [168]
3 years ago
5

Which quadratic equations have two solutions? Select all that apply.​

Mathematics
1 answer:
AnnZ [28]3 years ago
4 0
Sheeeeeesssshhhhhhhhh
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A city has a population of 38802500 people. Estimate this population to the nearest ten million
Ierofanga [76]

Answer:

40,000,000 or 40 million

Step-by-step explanation:

4 0
3 years ago
The elimination method works when the equations are in what form
egoroff_w [7]
The answer is standard form. When the equation is set up as Ax + By = C where A and B are coefficients. 
6 0
3 years ago
Write a coordinate proof to prove that the segment that joins the vertex angle of an isosceles triangle to the midpoint of its b
Natalija [7]

Answer:

Slope of the base segment line is zero, hence base segment is horizontal

Slope of the segment that joins the vertex angle to the midpoint of its base is undefined hence the line is vertical

Therefore, angle between base segment line and the segment line from the vertex angle to the midpoint is perpendicular

Therefore, the segment that joins the vertex angle to an isosceles triangle to the midpoint of its base is perpendicular to the base

Step-by-step explanation:

Here we prove the required relation as follows;

Let the isosceles be ABC

The coordinates of the points are

C = (0, 0) (Vertex)

A =  (-a, b)

C = (a, b)

P = (0, b) (Midpoint of base)

Therefore, the gradient or slope of the base AC is presented as follows;

Slope, m \, of \. base, \, AC= \frac{dy}{dx}  = \frac{b - b}{a - (-a)}  = \frac{0}{2\cdot a} = 0

Hence, segment AC is vertical

Slope, m \, of \, segment \ CP \,  joining \, vertex, \, to \, midpoint, P, on  \,AC = \frac{0 - b}{0 - 0}  = \frac{-b}{0} = Undifined.

Hence, segment CP is vertical

Therefore, the segment that joins the vertex angle to an isosceles triangle to the midpoint of its base is perpendicular to the base.

6 0
4 years ago
A field is to be fertilized at a cost of $0.07 per square yard. The rectangular part of the field is 125 yd long and the diamete
Dmitry [639]

Answer:

The cost of fertilizing the field is \$437.96

Step-by-step explanation:

we know that

The area of the figure is equal to the area of the rectangle plus the area of a complete circle (two semicircles)

Step 1

Find the area of the rectangle

The area of rectangle is equal to

A=LW

where

L is the length side of rectangle

w is the width side of the rectangle

In this problem we have

L=125\ yd

W=D=40\ yd

substitute

A=125*40=5,000\ yd^{2}

Step 2

Find the area of the circle

The area of the circle is equal to

A=\pi r^{2}

where

r is the radius of the circle

In this problem we have

r=40/2=20\ yd

substitute

A=\pi (20)^{2}=1,256.64\ yd^{2}

Step 3

Find the area of the figure

Adds the area of rectangle and the area of the circle

5,000\ yd^{2}+1,256.64\ yd^{2}=6,256.64\ yd^{2}

Step 4

Find the cost

Multiply the total area by 0.07 \frac{\$}{yd^{2} }

so

6,256.64*0.07=\$437.96

5 0
3 years ago
The arena has come to an agreement with the Sleaford Rockers to pay them according to this formula: b = tp- ( s + 2,000)
Anna35 [415]

if I am not mistaken your answer is 92,000. I hope this helps you good luck with l=your mathematics.

7 0
3 years ago
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