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Pepsi [2]
3 years ago
14

Will reward brainliest!

Mathematics
1 answer:
Lina20 [59]3 years ago
8 0

Option D: Two irrational solutions

Explanation:

The equation is 17+3 x^{2}=6 x

Subtracting 6x from both sides, we have,

3x^{2} -6x+17=0

Solving the equation using quadratic formula,

x=\frac{6 \pm \sqrt{36-4(3)(17)}}{2(3)}

Simplifying the expression, we get,

\begin{aligned}x &=\frac{6 \pm \sqrt{36-204}}{6} \\&=\frac{6 \pm \sqrt{-168}}{6} \\&=\frac{6 \pm 2 i \sqrt{42}}{6}\end{aligned}

Taking out the common terms and simplifying, we have,

\begin{aligned}x &=\frac{2(3 \pm i \sqrt{42})}{6} \\&=\frac{(3 \pm i \sqrt{42})}{3}\end{aligned}

Dividing by 3, we get,

x=1+i \sqrt{\frac{14}{3}}, x=1-i \sqrt{\frac{14}{3}}

Hence, the equation has two irrational solutions.

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