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juin [17]
2 years ago
7

Please help me with this​

Mathematics
1 answer:
Ann [662]2 years ago
3 0

Answer:

The correct answer is the last one

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Middle school students were asked how they got to school each morning. There were 375 students who said they rode the bus. This
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625 students

Step-by-step explanation:

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Anyone know how to do this? (10)
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MP = P - M = (0, 5) - (5, 6) = (0-5, 5-6) = (-5, -1) |MP| = √((-5)^2 + (-1)^2) = √(25+1) = √26
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98, 78, 84, 75, 91<br> What is the mean absolute deviation of his scores?
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85.2

Step-by-step explanation:

you add all the numbers together then you divide it by 5 then you have your answer.

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3 years ago
100 POINTS PLZ HELPPP Drag each tile to the correct box. Arrange the expressions in increasing order of their estimated values.
andrew11 [14]

Answer:

<h3>\frac{\sqrt{24}- \sqrt{54} }{\sqrt{6}} = -1   </h3><h3>\sqrt{\frac{9}{20}*\frac{10\sqrt{2} }{3\sqrt{5} } = 1.4142</h3><h3>\frac{10\pi\sqrt{2}-8\pi\sqrt{2}}{2\sqrt{2}}  = π =3.14159</h3><h3>\pi\sqrt{\frac{5}{3}}\cdot\pi\sqrt{\frac{3}{5}} = π² = 9.8696</h3>

Explanation:

1.) Rewrite √24 = \sqrt{4*6} = 2\sqrt{6}   Rewrite √54 =\sqrt{9*6}= 3\sqrt{6}

Divide both terms by the denominator; √6 cancels. 2-3 = -1

2.) Rewrite as \frac{3}{2\sqrt{5}} ×\frac{10\sqrt{2}}{3\sqrt{5}}  The 3's cancel.  10/2 = 5√2 in the numerator.

√5 × √5 = 5 in the denominator.  The 5's cancel.

That leaves √2 ≈1.4142

3.) Divide the terms in the numerator by the term in the denominator.

√2's cancel.  10π/2 = 5π   8π/2 = 4π  

Subtract and we are left with π = 3.14159

4.) \pi\sqrt{\frac{5}{3}}\cdot\pi\sqrt{\frac{3}{5}}  The square roots are reciprocals. They multiply to 1

We are left with π × π = π² ≈  9.8696

<h3> </h3>

8 0
3 years ago
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(WORTH 20 POINTS) Which relation could be rewritten using FUNCTION notation?
xz_007 [3.2K]

B) can be rewritten in function notation.

To find the function we must isolate y. To do this, we must subtract x from each side which will give us y=3-x

Now, we can replace y with f(x), so the function is

f(x) =3-x

4 0
3 years ago
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