Shortest to tallest: Plant A, Plant B, Plant C.
Given:
Plant A 1/3 inch tall
Plant B 3/4 inch tall
Plant C 5/6 inch tall
Order from shortest to tallest.
First we need to get the least common multiple of the three fractions.
Multiple of 3: 3, 6, 9, 12
Multiple of 4: 4, 8, 12, 16
Multiple of 6: 6, 12, 18
Their least common multiple is 12. We need to multiply each fraction by the number that will give the product of 12 to the denominator.
Plant A: 1/3 * 4/4 = 4/12
Plant B: 3/4 * 3/3 = 9/12
Plant C: 5/6 * 2/2 = 10/12
Since the denominator is common, we will use the numerator as basis in ordering the plants from shortest to tallest.
4 is less than 9 and 9 is less than 10.
so, Plant A is the shortest, Plant B is the medium height, and Plant C is the tallest.
X 1 2 ----- + ---- = ------- so the common denominator will be 4(2x-1) 2x-1 4 2x -1 4x +2x-1 8 ----------- = --------- 4(2x-1) 4(2x-1) 6x-1 8 ---------- = -------- make the restriction for x so 2x-1 =0 ,result x=1/2 4(2x-1) 4(2x-1) so what mean that x not can being equal 1/2 6x-1=8 6x = 9 x= 9/6 x = 3/2
Answer:
Step-by-step explanation:
The segment addition theorem tells you ...
CD +DE = CE
x^2 +12x = 32 -2x
Subtract the right side to put this in standard form.
x^2 +14x -32 = 0
(x +16)(x -2) = 0
x = -16 or 2
In order for DE to have a positive length, we must have x > 0. So ...
CD = x^2 = 2^2 = 4
DE = 12x = 12(2) = 24
CE = 32 -2x = 32 -2(2) = 28
Answer:
it 66
Step-by-step explanation:
