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Vedmedyk [2.9K]
2 years ago
9

Write the equation of a line that is perpendicular to y=3x-2 and that passes through the point (-9,5)

Mathematics
1 answer:
damaskus [11]2 years ago
8 0
Slope of perpendicular is -1/3.
Then equation is
y-5=(-1/3)(x+9)
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3 years ago
Find the midpoint of A and B where A has coordinates (-5, 3)<br> and B has coordinates (3,-1)
yaroslaw [1]

Answer:

(-1, 1)

Step-by-step explanation:

Midpoint formula: (x₁ + x₂/2 , y₁ + y₂/2)

Substitute the values into the formula.

(-5 + 3/2 , 3 - 1/2)

(-2/2 , 2/2)

(-1,1)

Therefore, the midpoint is (-1, 1).

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3 years ago
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The following data are the distances between a sample of 20 retail stores and a large distribution center. The distances are in
sesenic [268]

Answer:

Variance = 1,227.27

Standard deviation = 35.03

Step-by-step explanation:

To calculate these, we use the following formulas:

Mean = (sum of the values) / n

Variance = ((Σ(x - mean)^2) / (n - 1)

Standard deviation = Variance^0.5

Where;

n = number of values = 20

x = each value

Therefore, we have:

Sum of the values = 29 + 32 + 36 + 40 + 58 + 67 + 68 + 69 + 76 + 86 + 87 + 95 + 96 + 96 + 99 + 106 + 112 + 127 + 145 + 150 = 1,674

Mean = 1,674 / 20 = 83.70

Variance = ((29-83.70)^2 + (32-83.70)^2 + (36-83.70)^2 + (40-83.70)^2 + (58-83.70)^2 + (67-83.70)^2 + (68-83.70)^2 + (69-83.70)^2 + (76-83.70)^2 + (86-83.70)^2 + (87-83.70)^2 + (95-83.70)^2 + (96-83.70)^2 + (96-83.70)^2 + (99-83.70)^2 + (106-83.70)^2 + (112-83.70)^2 + (127-83.70)^2 + (145-83.70)^2 + (150-83.70)^2) / (20 - 1) = 23,318.20 / 19 = 1,227.27

Standard deviation = 1,227.27^0.5 = 35.03

5 0
2 years ago
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