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sergeinik [125]
2 years ago
15

The most Stanley can afford to pay per year in mortgage payments is $12,000, and his credit score is currently 544. According to

the following table for a $150,000 mortgage, by how many points would he need to improve his credit score in order to take a mortgage for $150,000? FICO Score 720-850 700-719 675-699 620-674 560-619 500-559 Interest Rate 5.59% 5.71% 6.25% 7.40% 8.53% 9.29% Monthly Payment $860 $872 $924 $1,039 $1,157 $1,238 O A. 156 points OB. 131 points O C. 76 points O D. 14 points​

Mathematics
1 answer:
stepan [7]2 years ago
5 0
B. Is the correct answer
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Help me please look at the file
Alchen [17]

Answer:

350 will be your answer :)

Step-by-step explanation:

so i did 70 divided by 2 because 140 divided by 70 = 2

and 70 divded by 2 IS 35!

But wait that isn't what it's asking for right?

then i did 35 TIMES 10 cuz that's what it;s asking for

i got 350 and so should you so in conclusion 350 is your answer

Hopefully this helped!

8 0
2 years ago
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3. The scale of a model car is 1:32.
Jlenok [28]

Answer: The answer would be 73.6

Step-by-step explanation: We have to 32x2.3 to get 73.6.

Hope this helps!

3 0
3 years ago
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What is a pie chart in mathematics
Ymorist [56]

Answer:

A pie chart is a type of graph that represents the data in a circular graph.

5 0
2 years ago
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PLEASE HELP! WILL MARK BRAINLIEST!!
Alecsey [184]

Answer:

The y-intercept is (0,1).  The x values at the horiz. intercepts are:

{ (-3+√5)/2, (-3-√5)/2 }.  Graph is that of a parabola that opens down.

Step-by-step explanation:

It'd be helpful to rewrite f(x) = 3-x2+3x-2 with the powers of x in descending order and using " ^ " to denote exponentiation:

f(x) = -x^2 + 3x -2 + 3, or

f(x) = -x^2 + 3x + 1

y-intercept:  let x = 0.  Then f(0) = 1.  The y-intercept is (0,1)

x-intercepts:  let y = f(x) = 0 = -x^2 + 3x + 1.  Let's use the quadratic formula with a = -1, b = 3 and c = 1 to determine the roots of this polynomial.  The discriminant, b^2-4ac, is 9-4(1)(1), or 5.

Thus, there are two real, unequal roots.  They are:

       -3 plus or minus √5

x =  ---------------------------------

                     2


or { (-3+√5)/2, (-3-√5)/2 }

These are your two horizontal intercepts, where the function is zero.

Because the coefficient -1 of the x^2 term is negative, the parabola representing this function opens down.

8 0
3 years ago
Suppose that you had the following data set. 500 200 250 275 300 Suppose that the value 500 was a typo, and it was suppose to be
hodyreva [135]

Answer:

\bar X_B = \frac{\sum_{i=1}^5 X_i}{5} =\frac{500+200+250+275+300}{5}=\frac{1525}{5}=305

s_B = \sqrt{\frac{\sum_{i=1}^5 (X_i-\bar X)^2}{n-1}}=\sqrt{\frac{(500-305)^2 +(200-305)^2 +(250-305)^2 +(275-305)^2 +(300-305)^2)}{5-1}} = 115.108

\bar X_A = \frac{\sum_{i=1}^5 X_i}{5} =\frac{-500+200+250+275+300}{5}=\frac{525}{5}=105

s_A = \sqrt{\frac{\sum_{i=1}^5 (X_i-\bar X)^2}{n-1}}=\sqrt{\frac{(-500-105)^2 +(200-105)^2 +(250-105)^2 +(275-105)^2 +(300-105)^2)}{5-1}} = 340.221

The absolute difference is:

Abs = |340.221-115.108|= 225.113

If we find the % of change respect the before case we have this:

\% Change = \frac{|340.221-115.108|}{115.108} *100 = 195.57\%

So then is a big change.

Step-by-step explanation:

The subindex B is for the before case and the subindex A is for the after case

Before case (with 500)

For this case we have the following dataset:

500 200 250 275 300

We can calculate the mean with the following formula:

\bar X_B = \frac{\sum_{i=1}^5 X_i}{5} =\frac{500+200+250+275+300}{5}=\frac{1525}{5}=305

And the sample deviation with the following formula:

s_B = \sqrt{\frac{\sum_{i=1}^5 (X_i-\bar X)^2}{n-1}}=\sqrt{\frac{(500-305)^2 +(200-305)^2 +(250-305)^2 +(275-305)^2 +(300-305)^2)}{5-1}} = 115.108

After case (With -500 instead of 500)

For this case we have the following dataset:

-500 200 250 275 300

We can calculate the mean with the following formula:

\bar X_A = \frac{\sum_{i=1}^5 X_i}{5} =\frac{-500+200+250+275+300}{5}=\frac{525}{5}=105

And the sample deviation with the following formula:

s_A = \sqrt{\frac{\sum_{i=1}^5 (X_i-\bar X)^2}{n-1}}=\sqrt{\frac{(-500-105)^2 +(200-105)^2 +(250-105)^2 +(275-105)^2 +(300-105)^2)}{5-1}} = 340.221

And as we can see we have a significant change between the two values for the two cases.

The absolute difference is:

Abs = |340.221-115.108|= 225.113

If we find the % of change respect the before case we have this:

\% Change = \frac{|340.221-115.108|}{115.108} *100 = 195.57\%

So then is a big change.

8 0
3 years ago
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