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2 years ago

[(25-11)+(15-9)]/5 Please help

2 answers:

6 0

First you subtract 11 from 25 and then subtract 9 from 15 and then add the differences together and then divide by 5 and you get 4.

hichkok12 [17]2 years ago

5 0

4
put it in a calculator and include all the parentheses

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An elliptical culvert is 3.5 feet tall and 6 feet wide. It is filled with water to a depth of 0.95 feet. Find the width of the s

maks197457 [2]

Answer:

$W_s \approx5.3$

Step-by-step explanation:

From the question we are told that

Height $H=3.5ft$

Weight $W= 6ft$

Depth $D=0.95ft$

Generally the equation for ellipses is given as

$\frac{x^2}{a^2} +\frac{y^2}{b^2} =1$

Where

$b=H/2\\b=3.5/2\\Therefore\\b=1.75\\a=W/2\\a=6/2\\Therefore\\a=3\\$

$\frac{x^2}{3^2} +\frac{y^2}{1.75^2} =1$

Generally to find y in the equation $\frac{x^2}{a^2} +\frac{y^2}{b^2} =1$

$y=-b+d$

$y=-1.75+0.95$

$y=-0.8$

Therefore

$\frac{x^2}{3^2} +\frac{(0.8)^2}{1.75^2} =1$

$\frac{x^2}{3^2} =1-\frac{(0.8)^2}{1.75^2}$

$\frac{x^2}{3^2} =1-0.2089795918$

$X^2 =3^2(1-0.2089795918)$

$X^2 =7.119183674$

$X =\sqrt{7.119183674}$

$X =2.66817984$

Therefore the width of the given stream is

$W_s=2.66817984*2$

$W_s=5.33635968$

$W_s \approx5.3$

3 0

2 years ago

Please help, please briefly explain, (awarded brainliest)

anastassius [24]

Answer:

Step-by-step explanation:

Its basically whatever point(s) meet exactly the on the x axis

4 0

2 years ago

Read 2 more answers

In a parking lot of 240 red and blue cars, the ratio of red cars to blue is 3:5

Kisachek [45]

Answer:

There would be 144 red cars.

Step-by-step explanation:

3:5 is equal to 3/5

240 * (3/5) = 144

8 0

3 years ago

Read 2 more answers

Simplify the expression so there is only one power for each base. (3x2)^5/(3^2 x 2^3)

Leya [2.2K]

Answer:

Option D

Step-by-step explanation:

(3×2)^5/(3^2×2^3)

=(3^5)(2^5)/(3^2)(2^3)

=(3^5)/3^2 × (2^5)/(2^3)

=(3^3)×(2^2)

7 0

3 years ago

What is the set builder notation of A={1,8,27,64,125}

Alex787 [66]

$A=\{1;\ 8;\ 27;\ 64;\ 125\}\\\\1^3=1\\2^3=8\\3^3=27\\4^3=64\\5^3=125\\\\Therefore,\ the\ set\ builder\ notation\ is:\\\boxed{A=\{y\in\mathbb{N}\ |\ y=x^3\ \wedge\ x\in\{1;\ 2;\ 3;\ 4;\ 5\}\}}$

3 0

3 years ago