Answer:
(x-5)^2+2
Step-by-step explanation:
To convert between standard and vertex form, you have to complete the square (which, as a reminder, (a+b)^2 = a^2+2ab+b^2).
Since a^2 is x^2, and 2ab is -10x, then b must be -5, so b^2 is 25. Therefore, we add and subtract 25 from the expression:
(x-10x+25)+27-25
Then, we can make (x-10x+25) to (x-5)^2:
(x-5)^2+2
Answer:
1000 cm2
Step-by-step explanation:
Pretty sure
S+d=209
d=209-s
6.5s+2d=836.5
6.5s+2(209-s)=836.5
6.5s+418-2s=836.5
4.5s+418=836.5
4.5s=418.5
s=93
There were 93 salads sold that day.
Answer:
Step-by-step explanation:
1) A similar triangle must have the same ratios of sides. Triangle ABC and triangle LNM are similar because all the sides of LNM are 1/2 of the sides of ABC. As they are all in a 1:2 ratio, the triangles are similar.
2) ADE and ABC are similar because each angle is the same. Angle D and Angle B are the same because they are shown as the same with the same dot symbolization. Angle E and C are the same because they are shown as the same with the same curvy angle representation. ADE and ABC share A as the same angle, so all three angles are the same.
5) As triangles ABC and EDC are similar, the sides must have the same ratio. ED is similar to AB, EC is similar to AC, and CD and BC are similar. First we find the ratio. The only pair of similar lines are EC and AC, so we have to find the ratio from those two lines. EC is 15 and AC is 10/3, so we do 15 divided by 10/3 and we get 9/2. Therefore, the ratio is 9/2. Now we can find x and y. We can first look at ED and AB. Ed is 12 and AB is y. We know that it must have the same ratio of 9/2, so 12/y must equal 9/2. We can do proportions. 12/y = 9/2, 9y = 24 (you multiply the numbers diagonally). So, we get y = 8/3. Now we can get x the same way. BC and CD are similar, and so x/5 must equal 9/2 as well. We use proportions again and we have x/5 = 9/2, so 45 = 2x and x = 45/2.
Answer:
240
Step-by-step explanation:
23^2 = a^2 + 17^2
529 = a^2 + 289
529 - 289 = a^2
240 = a ^ 2
240 is not a perfect square number
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