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3 years ago

Find the measure of the

Mathematics

1 answer:

Semmy [17]3 years ago

3 0

Answer:

Step-by-step explanation:

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What is log b^b^6x equivalent to (The b is under log and ^b)? How do you know?

Arturiano [62]

Answer: 6x

Work Shown:

For each step, the logs are all base b. This is to save time and hassle of writing tricky notation of having to write the smaller subscript 'b' multiple times. The first rule to use is that log(x^y) = y*log(x) for any base of a logarithm. The second rule is that $\log_b(b) = 1$ meaning that the log base of itself is 1

log(b^(6x)) = 6x*log(b) .... pull down exponent using the first rule above

log(b^(6x)) = 6x*1 .... use the second rule mentioned

log(b^(6x)) = 6x

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3 years ago

Enter the number that makes the equation true.

Mrrafil [7]

Answer:

Step-by-step explanation:

if you convert 0.26 into a fraction you get 26/100 so the answer is 26.

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3 years ago

Read 2 more answers

<img src="https://tex.z-dn.net/?f=%5Cboxed%7B%5Csf%202x%2B31%3D5%7D" id="TexFormula1" title="\boxed{\sf 2x+31=5}" alt="\boxed{\s

AleksAgata [21]

2x + 31 = 5

2x = 5 - 31

2x = -26

x = -26/2

x = -13.

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꧁✿ ᴿᴬᴵᴺᴮᴼᵂˢᴬᴸᵀ2222 ✬꧂

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3 years ago

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Select the correct answer. What is the domain of the function represented by this graph?

devlian [24]

Answer:

Doman is the x intercpet range

Step-by-step explanation:

all real numbers is the domain since the function goes on and on forever and will at one point get to 1 billion or trillion or just on and on forever.

8 0

3 years ago

The probability that a male will be colorblind is .042. Find the probabilities that in a group of 53 men, the following are true

Dvinal [7]

Answer:

See below for answers and explanations

Step-by-step explanation:

Part A

$\displaystyle P(X=x)=\binom{n}{x}p^xq^{n-x}\\\\P(X=5)=\binom{53}{5}(0.042)^5(1-0.042)^{53-5}\\\\P(X=5)=\frac{53!}{(53-5)!*5!}(0.042)^5(0.958)^{48}\\\\P(X=5)\approx0.0478$

Part B

$P(X\leq5)=P(X=1)+P(X=2)+P(X=3)+P(X=4)+P(X=5)\\\\P(X\leq5)=\binom{53}{1}(0.042)^1(1-0.042)^{53-1}+\binom{53}{2}(0.042)^2(1-0.042)^{53-2}+\binom{53}{3}(0.042)^3(1-0.042)^{53-3}+\binom{53}{4}(0.042)^4(1-0.042)^{53-4}+\binom{53}{1}(0.042)^5(1-0.042)^{53-5}\\\\P(X\leq5)\approx0.9767$

Part C

$\displaystyle P(X\geq 1)=1-P(X=0)\\\\P(X\geq1)=1-(1-0.042)^{53}\\\\P(X\geq1)\approx1-0.1029\\\\P(X\geq1)\approx0.8971$

6 0

2 years ago