Answer:
C is correct
Explanation:
For example, you move your hands together you are creating friction.
Answer:
4.8 g/mL is the density of chloroform vapor at 1.00 atm and 298 K.
Explanation:
By ideal gas equation:
Number of moles (n)
can be written as: 
where, m = given mass
M = molar mass
where,
which is known as density of the gas
The relation becomes:
.....(1)
We are given:
M = molar mass of chloroform= 119.5 g/mol
R = Gas constant = 
T = temperature of the gas = 
P = pressure of the gas = 1.00 atm
Putting values in equation 1, we get:
4.8 g/mL is the density of chloroform vapor at 1.00 atm and 298 K.
Atomic radius decreases with the increase of atomic number and mass number because the nuclear charge attracts the outermost shell leads to lower distance of the atom.
<h3>
What is the trend of atomic radius across the periodic table?</h3>
Atomic radius decreases when we go from left to right to a period and increases down a group. In a period, effective nuclear charge increases as electron shielding remains the same. An atom gets larger as the number of orbits or shells increases. The radius of atoms increases as you go down the group in the periodic table. The size of an atom will decrease as you move from left to the right in a period. Within a period, protons are added to the nucleus which attracts electrons closer to the nucleus because of its increased positive charge i.e. proton. So that's why we can say that the force of attraction between nuclei and electrons increases, the atomic radius of the atoms decreases.
So we can conclude that Atomic radius decreases with the increase of atomic number and mass number because the nuclear charge attracts the outermost shell leads to lower distance of the atom.
Learn more about atomic radius here: brainly.com/question/15255548
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The reaction is,
H2S + I2 --------------> 2 HI +S
Molar weight of H2S = 34 g per mol
Molar weight of HI =128 g per mol
Molar weight of I2 =254 g per mol
Moles of H2S in 49.2 g = 49.2 /34 mol = 1.447 mol
So according to stoichiometry of the reaction, number of I2 mols needed
= 1.447 mol
The mass of I2 needed = 1.447 mol x 254 g
