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mestny [16]
1 year ago
8

Application: Address incorrect information and explain correct reasoning

Chemistry
1 answer:
Flauer [41]1 year ago
3 0

Atomic radius decreases with the increase of atomic number and mass number because the nuclear charge attracts the outermost shell leads to lower distance of the atom.

<h3>What is the trend of atomic radius across the periodic table?</h3>

Atomic radius decreases when we go from left to right to a period and increases down a group. In a period, effective nuclear charge increases as electron shielding remains the same. An atom gets larger as the number of orbits or shells increases. The radius of atoms increases as you go down the group in the periodic table. The size of an atom will decrease as you move from left to the right in a period. Within a period, protons are added to the nucleus which attracts electrons closer to the nucleus because of its increased positive charge i.e. proton. So that's why we can say that the force of attraction between nuclei and electrons increases, the atomic radius of the atoms decreases.

So we can conclude that Atomic radius decreases with the increase of atomic number and mass number because the nuclear charge attracts the outermost shell leads to lower distance of the atom.

Learn more about atomic radius here: brainly.com/question/15255548

#SPJ1

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What is the equilibrium constant, KC if the reaction is a gas phase reaction? (Ans.: Gas: KC = 0.328 dm3/mol)
valentina_108 [34]

Answer:

Equilibrium constant Kc = Qc = quotient of reactant(s) and product(s)

Kc = [C]x[D]y..../[A]m[B]n..... = 0.328dm3/mol, where [C]x[D]y is the product and [A]m[B]n is the reactant(Both in gaseous states)

Explanation:

When a mixture of reactants and products of a reaction reaches equilibrium at a given temperature, its reaction quotient always has the same value. This value is called the equilibrium constant (K) of the reaction at that temperature. As for the reaction quotient, when evaluated in terms of concentrations, it is noted as Kc.

That a reaction quotient always assumes the same value at equilibrium can be expressed as:

Qc (at equilibrium) = Kc =[C]x[D]y…/[A]m[B]n…

This equation is a mathematical statement of the law of mass action: When a reaction has attained equilibrium at a given temperature, the reaction quotient for the reaction always has the same value.

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The hydrogen bonds aren't as strong as the covalent bonds in disulfides.

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6 0
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3 0
3 years ago
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4 0
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