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Sphinxa [80]
3 years ago
11

I’m not sure how to do solving and graphing inequalities

Mathematics
1 answer:
Juliette [100K]3 years ago
7 0

Answer:

its easy

Step-by-step explanation:

First you need to get your two numbers or more than to like for example 6 and 9 6<9 the alligator mouth would go to the 9 because its bigger and say for instances 9,10,5 it would be 9<10>5 ten is bigger than them all so there you go

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T/2 = 18/t <br> what is t
alina1380 [7]
You solve for t by cross multiplying and your result will be, t=6,-6
3 0
2 years ago
Read 2 more answers
Find the slope of the line.<br> - 3x – 2y = 7
Troyanec [42]

Answer:

-1.5

Step-by-step explanation:

7 0
3 years ago
Tickets for the baseball games were $2.50 for general admission and 50 cents for kids. If there were six times as many general a
Makovka662 [10]
There was 3000 general admission tickets sold and 500 kid ticket sold.

How did I get this?

First, we need to see what information we have.
$2.50 = General admission tickets = (G)
 $0.50 = kids tickets =  (K)
There were 6x as many general admission tickets sold as kids. G = 6K

We need two equations:
G = 6K  
$2.50G + $.50K = $7750
Since, G = 6K we can substitute that into the 2nd equation.

2.50(6K) + .50K = 7750
Distribute 2.50 into the parenthesis

15K + .50K = 7750
combine like terms

15.50K = 7750
Divide both sides by 15.50, the left side will cancel out.

K = 7750/15.50
K = 500 tickets
So, 500 kid tickets were sold.

Plug K into our first equation (G = 6k)

G = 6*500
G = 3000 tickets

So, 3000 general admission tickets were sold,

Let's check this:

$2.50(3000 tickets) = $7500 (cost of general admission tickets)
$.50(500 tickets) = $250 (cost of general admission tickets)
$7500 + $250 = $7750 (total cost of tickets)




4 0
3 years ago
Counted a total of 40 white cars and yellow cars there were 9 times as many as white cars as yellow cars. how many white cars di
Law Incorporation [45]
Let W = number of white cars, and Y = number of yellow cars.
There were 9 times as many white cars as yellow cars. This means that the number of white cars was 9 times more than the number of yellow cars. This can be translated by the expression:
9Y = W
The person counted  40 cars in total:
W + Y = 40

So we get the system:
\left \{ {{W+Y=40} \atop {9Y=W}} \right.

In the first equation, we multiply by 9:
9W + 9Y = 360
In the second equation:
9Y= W
W-9Y = 0

Then we add the first with the second equation:
9W + 9Y + W - 9Y = 360
10 W = 360
W = 36

So He counted 36 white cars.

Hope this Helps! :)

8 0
3 years ago
Differentiation. questions 1 and 2
drek231 [11]
For 11, we start by plugging 1 in, getting 2(1)^2+1-5=-2=y

Plugging 1+m instead, we get 2(1+m)^2+1+m-5=2(1+2m+m^2)+1+m-5
= 2+4m+2m^2+1+m-5= 2m^2+5m-2. We have to find the difference between that and -2, so 2m^2+5m-2 -(-2)=2m^2+5m

Differentiating 12, we use the Power Rule to get -6x^2+14, and plugging x=1 into it, we get -6(1)^2+14=-6+14=18
4 0
3 years ago
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