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Troyanec [42]
3 years ago
11

Combine like terms in the expression –5x + 2y + 5x – 8y.

Mathematics
2 answers:
iVinArrow [24]3 years ago
6 0
You need to combine -5x and 5x together and that would give you zero so you need to combine 2y and -8y which would give you -6y so the answer is C. -6y
fenix001 [56]3 years ago
5 0
C

-5x + 5x
0x

2y - 8y
-6y
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Which situation could be represented by the graph?
Y_Kistochka [10]

Answer:

A program at a community college can be completed in no fewer than 8 months, but must be completed in less than 11 months.

Step-by-step explanation:

1. The closed dot means the number is equal to and the open dot means the number is less/ greater than

2. The line goes right from the 8 with a closed dot, making x greater than or equal to 8

3. The line goes left from the 11 with an open dot, making x less than ll

4. This means the number must be equal to or greater than 8, and less than 11

9 0
3 years ago
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Hanna picks up strawberries. she can either choose getting 74$ per hour or 3 $ per basket. she says she can pick up 10 basket in
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Answer:

21.62% more

Step-by-step explanation:

20 mins * 3 = 60 mins (1 hour)

10 baskets * 3 = 30 baskets

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90$ - 74$ = 16$

74 / 100 - 0.74

90 / 0.74 = 121.62

So she makes 21.62% more with 3$ per basket.

8 0
3 years ago
Perform the indicated operations. Write the answer in standard form, a+bi.<br> 5-3i / -2-9i
Vsevolod [243]

\huge \boxed{\mathfrak{Answer} \downarrow}

\large \bf\frac { 5 - 3 i } { - 2 - 9 i } \\

Multiply both numerator and denominator of \sf \frac{5-3i}{-2-9i} \\ by the complex conjugate of the denominator, -2+9i.

\large \bf \: Re(\frac{\left(5-3i\right)\left(-2+9i\right)}{\left(-2-9i\right)\left(-2+9i\right)})  \\

Multiplication can be transformed into difference of squares using the rule: \sf\left(a-b\right)\left(a+b\right)=a^{2}-b^{2}.

\large \bf \: Re(\frac{\left(5-3i\right)\left(-2+9i\right)}{\left(-2\right)^{2}-9^{2}i^{2}})  \\

By definition, i² is -1. Calculate the denominator.

\large \bf \: Re(\frac{\left(5-3i\right)\left(-2+9i\right)}{85})  \\

Multiply complex numbers 5-3i and -2+9i in the same way as you multiply binomials.

\large \bf \: Re(\frac{5\left(-2\right)+5\times \left(9i\right)-3i\left(-2\right)-3\times 9i^{2}}{85})  \\

Do the multiplications in \sf5\left(-2\right)+5\times \left(9i\right)-3i\left(-2\right)-3\times 9\left(-1\right).

\large \bf \: Re(\frac{-10+45i+6i+27}{85})  \\

Combine the real and imaginary parts in -10+45i+6i+27.

\large \bf \: Re(\frac{-10+27+\left(45+6\right)i}{85})  \\

Do the additions in \sf-10+27+\left(45+6\right)i.

\large \bf Re(\frac{17+51i}{85})  \\

Divide 17+51i by 85 to get \sf\frac{1}{5}+\frac{3}{5}i \\.

\large \bf \: Re(\frac{1}{5}+\frac{3}{5}i)  \\

The real part of \sf \frac{1}{5}+\frac{3}{5}i \\ is \sf \frac{1}{5} \\.

\large  \boxed{\bf\frac{1}{5} = 0.2} \\

3 0
2 years ago
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Answer: 1 1/2

Step-by-step explanation:

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2 years ago
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mixas84 [53]
Answer would be 4 times

so if u count from behind 7 to where the decimal point is it would be 4


brainliewst and thanks plz
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3 years ago
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