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Mashcka [7]
3 years ago
13

You decide to record the hair colors of people leaving a lecture at your school. What is the probability that the next person wh

o leaves the lecture will have blonde hair
Mathematics
1 answer:
deff fn [24]3 years ago
4 0

This question is incomplete, the complete question is;

You decide to record the hair colors of people leaving a lecture at your school. What is the probability that the next person who leaves the lecture will have blonde hair ?

Express your answer as a simplified fraction or a decimal rounded to four decimal places.

Blonde Red Brown Black Gray

31          25       18      40     42

Answer: the probability that the next person who leaves the lecture will have blonde hair is 0.1987

Step-by-step explanation:

Given that;

HAIR COLOR      FREQUENCY

Blonde                         31

Red                              25

Brown                          18

Black                           40

Gray                            42

Total                           156

So

there were 156 people all together

and out of the 156, 31 of them were blonde.

now the probability that the next person who leaves the lecture will have blonde hair will be;

⇒ 31 / 156 = 0.1987

Therefore, the probability that the next person who leaves the lecture will have blonde hair is 0.1987

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2. 20m * $1.75 = $35. $70 - $35 = $35. Yes, she can cover the fare. Samantha has more than needed. She can afford the taxi fare and still have money left for future use.

7 0
3 years ago
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Identify the linear equation.
slamgirl [31]
I would go with D, it looks like it is the most linear out of the rest, Hope it helps:)
7 0
3 years ago
7 + 2y = 8x 3x - 2y = 0 Solve the system of equations by substitution. (70/3, 140/9) (7/5, 21/10) no solution coincident
Wittaler [7]
So we have the system of equations:
7+2y=8x equation (1)
3x-2y=0 equation (2)

To use substitution, we are going to solve for one variable in one of our equations, and then we are going to replace that value in the other equation:
Solving for x in equation (2):
3x-2y=0
3x=2y
x= \frac{2}{3}y equation (3)

Replacing equation (3) in equation (1):
7+2y=8x
7+2y=8( \frac{2}{3} y)
7+2y= \frac{16}{3} y
7= \frac{10}{3} y
y= \frac{7}{ \frac{10}{3} }
y= \frac{21}{10} equation (4)

Replacing equation (4) in equation (3):
x= \frac{2}{3}y
x=( \frac{2}{3} )( \frac{21}{10} )
x= \frac{7}{5}

We can conclude that the solution of our system of equations is <span>(7/5, 21/10)</span>
5 0
3 years ago
CAN SOMEONE PLZ HELP ME WITH THIS ONE
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Answer:

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Step-by-step explanation:

8 0
3 years ago
A teacher administers three different versions of a test to his students. The two-way table shows the results. Find each probabi
kakasveta [241]

The P(pass | Test A) is 31.81%, P(pass | Test B) is 29.87%, and P(pass | Test C) is 22.07%

<h3>What is probability?</h3>

It is defined as the ratio of the number of favourable outcomes to the total number of outcomes, in other words, the probability is the number that shows the happening of the event.

Part A:

Total number of students = 154

Total number of students passed the test = 49

The probability:

P(pass | Test A) = 49/154 = 31.81%

Part B:

Total number of students = 154

Total number of students passed the test = 46

The probability:

P(pass | Test B) = 46/154 = 29.87%

Similarly, for the probability:

P(pass | Test C) = 34/154 = 22.07%

Thus, the P(pass | Test A) is 31.81%, P(pass | Test B) is 29.87%, and P(pass | Test C) is 22.07%

Learn more about the probability here:

brainly.com/question/11234923

#SPJ1

5 0
3 years ago
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