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inessss [21]
3 years ago
6

Solve the compound inequality 7x ≥ –56 and 9x < 54

Mathematics
1 answer:
Reptile [31]3 years ago
5 0

Answer:

For the first inequality-   (-8)

Second inequality-    6

Step-by-step explanation:

First inequality- divide both sides by 7.

Second inequality- divide both sides by 9

Hope this helps ^-^

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Alicia ran 5 miles over the weekend. Approximately how many kilometers did she run? [Use the conversion 1 mile ≈ 1.6 kilometers.
Svet_ta [14]

Answer:

Total distance Alicia run in kilometer = 8 Kilometer

Step-by-step explanation:

Given:

Total distance Alicia run = 5 miles

1 mile ≈ 1.6 kilometer

Find:

Total distance Alicia run in kilometer

Computation:

Total distance Alicia run in kilometer = 1.6 × 5

Total distance Alicia run in kilometer = 8 Kilometer

3 0
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snow_tiger [21]

Answer:

x = 1.5

Step-by-step explanation:

First, calculate 6-9, which is -3.

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Then divide by 4 on both sides to get x = 1.5

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3 years ago
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Lunna [17]
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3 years ago
Find an equation of the sphere with center (2, −10, 3) and radius 5. $$25=(x−2)2+(y−(−10))2+(z−3)2 use an equation to describe i
lana66690 [7]

In the x,y plane, we have z=0 everywhere. So in the equation of the sphere, we have

25=(x-2)^2+(y+10)^2+(-3)^2\implies(x-2)^2+(y+10)^2=16=4^2

which is a circle centered at (2, -10, 0) of radius 4.

In the x,z plane, we have y=0, which gives

25=(x-2)^2+10^2+(z-3)^2\implies(x-2)^2+(z-3)^2=-75

But any squared real quantity is positive, so there is no intersection between the sphere and this plane.

In the y,z plane, x=0, so

25=(-2)^2+(y+10)^2+(z-3)^2\implies(y+10)^2+(z-3)^2=21=(\sqrt{21})^2

which is a circle centered at (0, -10, 3) of radius \sqrt{21}.

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3 years ago
Eleven more than six times a number is twenty-three
Natali5045456 [20]
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2 years ago
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