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Simora [160]
3 years ago
9

Jasmine is thinking about buying a car and is comparing two vehicles. One gets 14 miles to the gallon (mpg) and the other gets 2

8 miles to the gallon. Assuming that she drives 6,000 miles a year, how much money would she save by buying the more fuel efficient car if gas is $3.50 a gallon? (Round to the nearest dollar.)
Mathematics
1 answer:
const2013 [10]3 years ago
3 0

The more fuel efficient car is the car that has 28 miles to a gallen.She would be saving 752 dollars.

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Question 1 C

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Christine buys 7 hamburgers and 3 sodas for $27.95. Laura buys 5 hamburgers and 4 sodas for $23.40. How much does a hamburger co
Naddika [18.5K]
7h+3s=27.95 subtract 7h from both sides

3s=27.95-7h  divide both sides by 3

s=(27.95-7h)/3

Then we are told:

5h+4s=23.4,  using s found above makes this equation become:

5h+4(27.95-7h)/3=23.4  multiply both sides by 3

15h+4(27.95-7h=70.2  perform indicated multiplication on left side

15h+111.8-28h=70.2 combine like terms on left side

-13h+111.8=70.2 subtract 111.8 from both sides

-13h=-41.6  divide both sides by -13

h=$3.20
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I cannot solve this.. i want to solve this
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What is the longest side of a right angled triangle called?
Anarel [89]

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The hypotenuse

4 0
3 years ago
Read 2 more answers
Assume V and W are​ finite-dimensional vector spaces and T is a linear transformation from V to​ W, T: Upper V right arrow Upper
scZoUnD [109]

Answer:

Thus for the vectors v_1, v_2, v_p there are scalars c_1, c_2, c_p not all zeros, such that c_1v_1 +c_2v_2+... +c_pv_p = 0. It means that the vectors v_1, v_2, v_p are linearly dependent in contradiction with the fact that the vectors form a basis for H. So the assumption that T(v_1), T(v_2),..., T(v_p) are linearly dependent is false, proving the required.  

Step-by-step explanation:

Let B = {v_1 ,v_2,..., v_p} be a basis of H, that is dim H = p and for any v ∈ H there are scalars c_1 , c_2, c_p, such that v = c_1*v_1 + c_2*v_2 +....+ C_p*V_p It follows that  

T(v) = T(c_1*v_1 + c_2v_2 + ••• + c_pV_p) = c_1T(v_1) +c_2T(v_2) + c_pT(v_p)

so T(H) is spanned by p vectors T(v_1),T(v_2), T(v_p). It is enough to prove that these vectors are linearly independent. It will imply that the vectors form a basis of T(H), and thus dim T(H) = p = dim H.  

Assume in contrary that T(v_1 ), T(v_2), T(v_p) are linearly dependent, that is there are scalars c_1, c_2, c_p not all zeros, such that  

c_1T(v_1) + c_2T(v_2) +.... + c_pT(v_p) = 0

T(c_1v_1) + T(c_2v_2) +.... + T(c_pv_p) = 0

T(c_1v_1+ c_2v_2 ... c_pv_p) = 0  

But also T(0) = 0 and since T is one-to-one, it follows that c_1v_1 + c_2v_2 +.... + c_pv_p = O.

Thus for the vectors v_1, v_2, v_p there are scalars c_1, c_2, c_p not all zeros, such that c_1v_1 +c_2v_2+... +c_pv_p = 0. It means that the vectors v_1, v_2, v_p are linearly dependent in contradiction with the fact that the vectors form a basis for H. So the assumption that T(v_1), T(v_2),..., T(v_p) are linearly dependent is false, proving the required.  

8 0
3 years ago
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