How many total atoms are there in 69.1 grams of ammonia (NH3)

How do you rewrite 6/9 in two different ways

Naya [18.7K]

We have to represent the fraction $\frac{6}{9}$ in two different ways.

Let us multiply the numerator and denominator of the given fraction by '2'.

Therefore, $\frac{6}{9} = \frac{6 \times 2}{9 \times 2} = \frac{12}{18}$

Therefore, $\frac{12}{18}$ is the first way to represent the given fraction.

Now, Let us multiply the numerator and denominator of the given fraction by '3'.

Therefore, $\frac{6}{9} = \frac{6 \times 3}{9 \times 3} = \frac{18}{27}$

Therefore, $\frac{18}{27}$ is the second way to represent the given fraction.

Therefore, $\frac{12}{18}$ and $\frac{18}{27}$ are the different ways to represent the fraction $\frac{6}{9}$ .

4 0

3 years ago

Scientist are studying a bacteria sample. The function f(x)=360(1.07)^x gives the number of bacteria in the sample at the end of

Lapatulllka [165]

Options :

A. The initial number of bacteria is 7.

B. The initial of bacteria decreases at a rate of 93% each day.

C. The number of bacteria increases at a rate of 7% each day.

D. The number of bacteria at the end of one day is 360.

Answer:

C. The number of bacteria increases at a rate of 7% each day.

Step-by-step explanation:

Given the function :

f(x)=360(1.07)^x ; Number of bacteria in sample at the end of x days :

The function above represents an exponential growth function :

With the general form ; Ab^x

Where A = initial amount ;

b = growth rate

x = time

For the function :

A = initial amount of bacteria = 360

b = growth rate = (1 + r) = 1.07

If ; (1 + r) = 1.07 ; we can solve for r to obtain the daily growth rate ;

1 + r = 1.07

r = 1.07 - 1

r = 0.07

r as a percentage ;

0.07 * 100% = 7%

7 0

3 years ago

If 55% is 70.4 so what is hundred percent

hodyreva [135]

Answer:

55%=70.4

1%=70.4/55= 1.28

100%=1.28into 100 = 128

8 0

3 years ago

Evaluate using the order of operations ( 8/9 - 1/3) x 2/3

Korvikt [17]

(8/9-3/9)*2/3=5/9*2/3=10/27

4 0

4 years ago

Read 2 more answers

Consider the two data sets below:

alina1380 [7]

Answer:

Option c) The data sets will have the same values of their interquartile range.

Explanation:

1. The values are in order: they are in increasing oder, from lowest to highest value.

2. Calculate the interquartile range.

Interquartile range, IQR, is the third quartile, Q3, less the first quartile Q1:

IQR = Q3 - Q1

To find the first and the third quartile, first find the median:

Data Set 1: 19, 25, 35, 38, 41, 49, 50, 52, 59

[19, 25, 35, 38], 41, [49, 50, 52, 59]

↑

median = 41

Data Set 2: 19, 25, 35, 38, 41, 49, 50, 52, 99

[19, 25, 35, 38] , 41, [49, 50, 52, 99]

↑

median = 41

Now find the median of each subset: the values below the median and the values above the median.

Data set 1: First quartile

[19, 25, 35, 38],

↑

Q1 = [25 + 35] / 2 = 30

Third quartile

[49, 50, 52, 59]

↑

Q3 = [50 + 52] / 2 = 51

IQR = Q3 - Q1 = 51 - 30 = 21

Data set 2: First quartile

[19, 25, 35, 38]

↑

Q1 = [25 + 35] / 2= 30

Third quartile

[49, 50, 52, 99]

↑

Q3 = [52 + 50]/2 = 51

IQR = 51 - 30 = 21

Thus, it is shown that the data sets have will have the same values for the interquartile range: IQR = 21. (option c)

This happens because replacing one extreme value (in this case the maximum value) by other extreme value does not affect the median.

An outlier will change the range because the range is the maximum value less the minimum value.

5 0

3 years ago

How many total atoms are there in 69.1 grams of ammonia (NH3)​

How many total atoms are there in 69.1 grams of ammonia (NH3)