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Anastasy [175]
3 years ago
13

A company is about to launch a new cell phone model. In the past, 40% of its cell phones have launched successfully. Before any

cell phone is launched, the company conducts market research and receives a report predicting favorable or unfavorable sales. In the past, 70% of successful cell phones and 20% of unsuccessful cell phones received favorable reports. What is the probability that the new cell phone will receive a favorable report, given that the cell phone launch is successful?
Mathematics
2 answers:
Eva8 [605]3 years ago
3 0
There is a 70% chance that te phone will receive a favorable report.
postnew [5]3 years ago
3 0

Answer:

The required probability is 0.70.

Step-by-step explanation:

Let A represents the event of launching successfully, B represents the event of receiving favourable reports,

Given,

Probability of successful launching,

P(A)=40\%=\frac{40}{100}=0.40

Also, 70% of successful cell phones are received favorable reports.

\implies P(A\cap B)=70\%\text{ of P(A)}=\frac{70\times 0.40}{100}=0.28

Thus, by the conditional property,

The probability that the new cell phone will receive a favorable report, given that the cell phone launch is successful,

P(\frac{B}{A})=\frac{P(A\cap B)}{P(A)}=\frac{0.28}{0.40}=0.70

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Answer:

square root, 2,12/5,2.47

Step-by-step explanation:

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What is the value of x that makes the given equation true?<br> X-3x=2(4+x)
Ratling [72]

x - 3x = 2(4 + x)

-2x = 8 + 2x

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Arrange the entries of matrix A in increasing order of their cofactors values
givi [52]

To find the cofactor of

A=\left[\begin{array}{ccc}7&5&3\\-7&4&-1\\-8&2&1\end{array}\right]

We cross out the Row and columns of the respective entries and find the determinant of the remaining 2\times 2 matrix with the alternating signs.


Ac_{11}=\left|\begin{array}{ccc}4&-1\\2&1\end{array}\right|


Ac_{11}=4\times 1- -1\times 2


Ac_{11}=4+ 2

Ac_{11}=6




Ac_{12}=-\left|\begin{array}{ccc}-7&-1\\-8&1\end{array}\right|


Ac_{12}=-(-7\times 1- -1\times -8)


Ac_{12}=-(-7- 8)

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Ac_{21}=-\left|\begin{array}{ccc}5&3\\2&1\end{array}\right|


Ac_{21}=-(5\times 1- 3\times 2)


Ac_{21}=-(5-6)


Ac_{21}=1







A_c{23}=-\left|\begin{array}{ccc}7&5\\-8&2\end{array}\right|


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Ac_{31}=5\times -1 -4\times 3


Ac_{31}=-5-12


Ac_{31}=-17


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Ac_{33}=7\times 4- -7\times 5


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Therefore in increasing order, we have;

Ac_{31}=-17,Ac_{21}=1,Ac_{11}=6,Ac_{23}=26,Ac_{12}=15, Ac_{33}=63



7 0
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<u>Step-by-step explanation:</u>

Given data:

The cost of renting of a scooter is represented by 3j +5

So, from that, we can say in general,

The cost of renting of n scooters is represented by  

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But according to given, the value of n is 6. i.e. to find the cost for six number of scooters. We can calculate now as follows

So, the cost of renting of a scooter is represented by  

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3 0
3 years ago
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