QR=9
QP=6
TU=19
TS=?
Okay so the triangles are kindred, now the equation can be made
9/16=6/x
So now we are going to cross multiply
9x=114
Now divide both sides by
912 2/3
Your answer is:
TS=12.6
Answer:
perpendicular (90 deg to each other)
Step-by-step explanation:
The surface area of the regular hexagonal pyramid is
SA = (1/2) pl + B
where p is the perimeter of the base, l is the slant height of the pyramid, and B is the area of the base
The area of a regular hexagon is 3 sh
where s is the length of the side and h is the length of the apothem.
So,
SA = (1/2)(6)(12) (11) + 3(12)(6sqrt3)
SA = 770 square meters
14 = 9 - x
First, subtract 9 from both sides.
14 - 9 = (9 - 9) - x
5 = -x
Now divide both sides by -1.
5/-1 = -1/-1x
-5 = x
The answer is x = -5.
yes it is right when the vertex of the first polygon is located on 3 - 2 after rotation the work vertex will be there on (2 , 3) it is right