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Strike441 [17]
2 years ago
8

Can someoneone help me with please i have to sent it today

Mathematics
1 answer:
ser-zykov [4K]2 years ago
8 0

Answer:

I was asleep in bed one night when, suddenly, a loud noise woke me. I did not know what it was I searched around for a few minutes, but I couldn't find where the sound was coming from, but on the floor, I saw a broken wase, and i decided to throw it away in the open window next to me... My house was very far out, hidden behind trees, and darkness was around me. Ahhh! The sound was repeating again and again so I decided to rush over to my phone to call the police. but then I realized that was just not any sound, but it was a cry for help. The police said they will send over a rescue worker to help me, to help them, whoever it is. I went downstairs to find something sharp something that could help me or at least scare away the person here.

Step-by-step explanation:

Hope you like it xD It is not 100% finished so probably you can finish it, i wrote an introduction for you) good luck

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Given that CD¯¯¯¯¯¯¯¯ is a perpendicular bisector of AB¯¯¯¯¯¯¯¯, where D is on AB¯¯¯¯¯¯¯¯, how can you use the Pythagorean Theor
Liula [17]

Answer:

(AD)^2 + (CD)^2 = (CA)^2 and (CD)^2 + (BD)^2 = (CB)^2

Step-by-step explanation:

Given

Bisector: CD

of Line AB

Required

Apply Pythagoras Theorem

From the question, CD bisects AB and it bisects it at D.

The relationship between AB and CD is given by the attachment

Considering ACD

From the attachment, we have that:

Hypothenuse = CA

Opposite = CD

Adjacent = AD

By Pythagoras Theorem, we have

(AD)^2 + (CD)^2 = (CA)^2

Considering CBD

From the attachment, we have that:

Hypothenuse = CB

Opposite = CD

Adjacent = BD

By Pythagoras Theorem, we have:

(CD)^2 + (BD)^2 = (CB)^2

4 0
3 years ago
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Which number is a factor of 14 but not a multiple of 2
GalinKa [24]
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3 years ago
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